Answer:
There are not 15 failures and 15 successes. A confidence interval can be computed by adding 2 failures and 2 successes .
Step-by-step explanation:
Given that
Survey asked by 40 people
6 said that they were very concerned.
So the following statements correctly describe the above problem
The correct statement is , There are not 15 failures and 15 successes. A confidence interval can be computed by adding 2 failures and 2 successes .
Given that:
mean,μ=35.6 min
std deviation,σ=10.3 min
we are required to find the value of x such that 22.96% of the 60 days have a travel time that is at least x.
using z-table, the z-score that will give us 0.2296 is:-1.99
therefore:
z-score is given by:
(x-μ)/σ
hence:
-1.99=(x-35.6)/10.3
-20.497=x-35.6
x=35.6-20.497
x=15.103
Answer:
To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic
1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation
We simplify and check the number of real roots with the quadratic formula, 
for quadratic equations the form 0 = a·x² - b·x + c
Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.
Step-by-step explanation:
Answer:
He could have 4 dimes, or 8 nickles, or 1 quater and 3 nickels, or 1 quater with one dime and 1 nickel, or 3 dimes and 2 nickles, or 1 quater with obe nickel and one dime.
Step-by-step explanation:
hope this helps.
If one labour works 200 hours per month, the amount of hot water heaters the labour can produce is = 200 × 0.25 = 50 hot water heaters
The demand is to produce 57600 hot water heaters
The number of labourers employed is 57600 ÷ 50 = 1152 labourers
