Answer:
Step-by-step explanation:
Let Alex's age = x
Mark's age = y
Luke's age = a
x + y + z = 12
The possible combinations for their age are
1. 6, 3, 3
2. 3, 3, 6
3. 4,4, 4
4, 2, 2, 8
5. 8, 2, 2
6. 2, 8, 2
7. 9, 2, 1
Etc the age can keep going as long as you can find any three numbers and add them to give you 12
Answer:
y=-10x
Step-by-step explanation:
y=-10x
y/x=-10
First of all, this is not an observational study, but an experiment, since we have two groups and one of the two groups is manipulated or treated. In an observational study the subjects are only observed.
Second, the students did not choose their groups - so we can't choose the last answer.
Therefore the correct answer is:
This is an experiment because a treatment was applied to a group.
Answer:
<em>55mph
. None of the options are correct
</em>
Step-by-step explanation:
If the speed varies inversely as the time it takes to drive, then v ∝ 1/t. where;
v is the speed
t is the time taken
Hence;
v = k/t with k being the constant of proportionality.
Since it takes Kris 5 hours when driving at 55 mph, we will substitute v = 55mph and t = 5 hours. into the equation above to get the value of k as shown:
55 = k/5
Cross multiply
k = 55*5
k = 275
Hence, to calculate the speed it will Martin to drive for 5 hours, we will substitute k = 275 and t = 5 into the original equation v = k/t as shownl
v = 275/5
v = 55 mph
<em>Hence, we can conclude that Martin will also need to drive at a speed of 55mph if he wants to take 5hours.</em>
Answer:
He should spend 3 minutes or less on each scale
Sven made a mistake in the symbol of inequality, placing lesser or equal instead of greater or equal
Step-by-step explanation:
Let
t ------> is the number of minutes he spends on each scale
Remember that the phrase "at least" is equal to "greater than or equal"
so
The inequality that represent this scenario is
solve for t
Multiply by -1 both sides
Divide by 5 both sides
Sven is incorrect
He should spend 3 minutes or less on each scale
Sven made a mistake in the symbol of inequality, placing lesser or equal instead of greater or equal
