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lana66690 [7]
2 years ago
7

Today the price of a Jeep is $25,000. In 1970, the price was $5,000. What's the price relative?

Mathematics
2 answers:
asambeis [7]2 years ago
6 0

Solution:

we are given with

Today the price of a Jeep is $25,000. In 1970, the price was $5,000.

So we can write

The price of a Jeep, today = $25,000

The price of a Jeep,in 1970 = $ 5,000

Relative Price means price of a good relative to other. Its a ratio of the two goods times 100.

Price   \ \ relative =\frac{25000}{5000}*100\\ \\ \  Price   \ \ relative =5*100=500\\ \\

Hence the price relative is $500/-

Jet001 [13]2 years ago
6 0

Answer:

<em>The price relative is  $500.</em>

Step-by-step explanation:

The  price relative of a good or service involves comparing the current prices of goods and services with a previous year. it is the percent ratio of the two prices, the price relative can be obtained using equation 1.

Price relative = (Current price/previous price) x 100 .....................1

Given

         Current price = $25,000

          Previous price = $5,000

Price relative = ($25,000 / $5,000) x 100

price relative =  $ 5 x 100

Price relative = $ 500

Therefore the price relative is $ 500

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I think the volume of cylinder B will be the same as that of cylinder A that is 360cm³
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Alan says that two lines in the coordinate plane are perpendicular if and only if the slopes of the lines are m and 1m. Identify
mart [117]

Answer:

First, two lines are perpendicular if one has slope m, and the other has slope -1/m (Not 1m as Alan says)

That is the first error of Alan.

Now, there is another error.

If m = 0, then -1/m tends to minus infinity (in this case we would have a vertical line).

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m can not be zero, if a line is horizontal, the perpendicular line must be vertical.

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2 years ago
6. Charlie can spend up to $8 on lunch. He wants to buy a tuna sandwich, a bottle of
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Answer:

The maximum number of pounds of potato salad that Charlie can buy is 0.375

Step-by-step explanation:

see the attached figure to better understand the problem

Let

a ----> the cost of one tuna sandwich

b ----> the cost of a bottle of apple juice

c ----> the cost per pound of potato salad

x ----> pounds of potato salad

we have

a=\$4.25

b=\$2.25

c=\$4.00/lb

we know that

He wants to buy a tuna sandwich, a bottle of  apple juice, and x pounds of potato salad and can spend up to $8

The inequality that represent this situation is

a+b+cx \leq 8

substitute the given values

4.25+2.25+4.00x \leq 8

Solve for x

Combine like terms

6.50+4.00x \leq 8

Subtract 6.50 both sides

4.00x \leq 8-6.50

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Divide by 4 both sides

x \leq 1.50/4.00

x \leq 0.375\ lbs

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The maximum number of pounds of potato salad that Charlie can buy is 0.375

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2 years ago
Mika estimated the sum of 189.27, 15.8, and 11.2 by rounding each number to the nearest whole.
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Answer:

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Step-by-step explanation:

Let's find the rounded sum and the actual sum, as follows:

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11.2 ⇒ 11

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7 0
2 years ago
The parallel dotplots below display the girths (belly
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Answer:

The standard deviation for the distribution of girths is

about the same for both male and female pigs.

Step-by-step explanation:

Step 1

We will interprete the dotplots

For the Male pigs

24, 26, 26, 26, 26, 26, 26, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 30, 30, 30, 30, 30, 30, 32

Range

Maximum value - Minimum value

= 32 - 24

= 8

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 26

7th value = 26

Q1 = 26 + 26/2

Q1 = 26

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 30

20th value = 30

Q3= 30+ 30/2

= 30

IQR = 30 - 26

= 4

Standard deviation

Mean

First we find the mean

= 24+ 26+26+ 26+ 26+ 26+26+28+ 28+ 28+ 28+28+ 28+ 28+28+ 28+28+28+30+ 30+30+ 30+30+30+32/28

= 700/25

= 28

Standard deviation Formula = √(x - mean)²/n - 1

= √[(24-28)² + (26- 28)² + (26 -28)² + (26 - 28)² +................ (32 - 28)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Female Pigs

21, 23, 23, 23,23,23,23,25, 25, 25, 25, 25, 25, 25, 25, 25, 25,25, 27, 27, 27, 27,27, 27, 29

Range:

Maximum value - Minimum value

= 29 - 21

8

IQR

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 23

7th value = 23

Q1 = 23 + 23/2

Q1 = 23

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 27

20th value = 27

Q3= 27+ 27/2

Q3 = 27

IQR = 27 - 23

= 4

First we find the Mean

=(21+23+23+23+23+23+23+25+ 25+ 25+ 25+25+ 25+ 25+ 25+25+25+25+27+27+ 27+27+27+ 27+29)/25

= 625/25

= 25

Standard deviation Formula = √(x - mean)²/n - 1

= √[(21-25)² + (23- 25)² + (23 -25)² + (23 - 25)² +................ (29 - 25)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Looking at the calculation above and comparing both the girths from the male and female

We can conclude that: The standard deviation for the distribution of girths is

about the same for both male and female pigs which is 1.825741858

5 0
2 years ago
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