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lana66690 [7]
2 years ago
7

Today the price of a Jeep is $25,000. In 1970, the price was $5,000. What's the price relative?

Mathematics
2 answers:
asambeis [7]2 years ago
6 0

Solution:

we are given with

Today the price of a Jeep is $25,000. In 1970, the price was $5,000.

So we can write

The price of a Jeep, today = $25,000

The price of a Jeep,in 1970 = $ 5,000

Relative Price means price of a good relative to other. Its a ratio of the two goods times 100.

Price   \ \ relative =\frac{25000}{5000}*100\\ \\ \  Price   \ \ relative =5*100=500\\ \\

Hence the price relative is $500/-

Jet001 [13]2 years ago
6 0

Answer:

<em>The price relative is  $500.</em>

Step-by-step explanation:

The  price relative of a good or service involves comparing the current prices of goods and services with a previous year. it is the percent ratio of the two prices, the price relative can be obtained using equation 1.

Price relative = (Current price/previous price) x 100 .....................1

Given

         Current price = $25,000

          Previous price = $5,000

Price relative = ($25,000 / $5,000) x 100

price relative =  $ 5 x 100

Price relative = $ 500

Therefore the price relative is $ 500

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bogdanovich [222]

Answer:

D. About $10

Step-by-step explanation:

To find unit price, you divide the total price by how much you're buying.

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7 0
2 years ago
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Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

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Landing on a number less than 2 would be 1.

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6 0
2 years ago
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6 questions = 30 points someone please help me
eduard

Answer:

1)D

2)D

3)A

4)B

5)Cannot Answer - No data

6)C

7)C

6 Questions answered for 30 points.

Step-by-step explanation:

Answer for the 1st Question,

Area of a cylinder can be calculated by,

Area of the cylindrical part = 2\pi rL

Area of the parts that cover the open parts of cylinder = 2\pi r^2

Therefor Total are of the cylinder = 2\pi rL+2\pi r^2

Area of the total cylinder = 2*3.14*6.8*14.2+2*3.14*6.8^2

                                          =896.784

<u>Therefor best estimate will be D) 923 in^2</u>


Answer for the 2nd Question,

ABC is a triangle.

By Pythagorean theorem it says,

(AC)^2+(CB)^2=(AB)^2

The distance from A to C = 6

The distance from C to B = 5

(AC)^2=6^2=36

(CB)^2=5^2=25

(AC)^2+(CB)^2=(AB)^2=36+25=61

Therefor (AB)^2=61\\(AB)=\sqrt{61}

<u>Therefor Answer is D) Sqr 61</u>

Answer to Question 3

To find the trend you can draw an imaginary line that fits the scatter plots.(I have attached a image drawing the imaginary lines)

Then the revenue can be calculated by calculating the area covered by the imaginary line drawn or area "under" the curve.

Area of the Store 1 =\frac{1}{2} *(110+40)*110=8250

Area of the Store 2=\frac{1}{2} *110*80=4400

Therefore Revenue from Store 1 = $8250

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<u>Answer is A) Store 1  has more sales revenue</u>

Answer for Question 4

\frac{5}{12}=0.4167\\\frac{5}{11}=0.4545

You can straight away discard answer D because it is less than both 5/12 and 5/11.

Also you can discard Answer C because 25/264 is very small (less than 1/10=0.1)

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Then it has to be \frac{115}{264} =0.4356

<u>Answer is B)</u>


Answer for question 6

The equation of a straight line is of the form y=mx+c

here m is the gradient and c is the intercept.

Find the intercept(c) by finding the y value when x value is 0, here it is +1.

Gradient (m) of the graph can be found by,

\frac{y1-y2}{x1-x2} =\frac{7-3}{3-1} =2

Therefor the equation of the graph is,

y=2x+1

<u>Answer is C</u>

Answer for question 7

\frac{7}{8} =0.875

\frac{6}{9} =0.67

We can discard answer A because the value is close to 0.5

We can discard answer B because 3/17 is a very small value (0.17)

\frac{53}{72} =0.73, This falls between the above 2 numbers.

<u>Therefor answer is C</u>


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zhannawk [14.2K]

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