Answer:
(b) 1/792
Step-by-step explanation:
The complete question is;
<em>Counting: Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.</em>
<em>(a) How many different groups of 5 problems can be chosen from the 12</em>
<em>problems?</em>
<em>(b)Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?</em>
<u>In (a)</u>
<u></u>
Apply the formula
where n=12 and r=5
substitute values
In (b)
If Jerry did only 5 problems of one assignment then the probability will be
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Answer:
Professor 1 as he gave the maximum number of A's .
This is sort of weird to write without any numbers, but it's not too hard. take your info out of the word problem:
fit fast = fee per class
stepping up = fee per class + monthly fee
now you just change all of that into variables, essentially:
F = cx
S = cx + m
so, fit fast is the cost of classes (c) times the number of classes taken (x). stepping up is the cost of classes times x, PLUS that additional monthly fee (m).
Answer:
Their headquarters contains <u>420000</u> employees.
Step-by-step explanation:
The company has two office buildings which hold 30,000 employees.
The headquarters contains 14 times as many employees as the overseas branch.
Therefore, the number of employees in the headquarters is:
14 * 30000 = 420000 employees
Their headquarters contains 420000 employees.
Answer:
There is no significant difference between the means.
Step-by-step explanation:
Given is the data set for X1 and x2 are we have to do a paired t test.
(Two tailed test at 5% significance level)
Mean difference = 1.00
Std error for difference = 1.225
df=4
Test statistic = mean diff/se = 1.826
p value =0.142
Since p >0.05 our alpha we accept H0
There is no significant difference before and after averages at 5% sign. level.
