Answer: A
Step-by-step explanation:
CORRECTED QUESTION
Joe walks on a treadmill at a constant rate. The equation d=4t describes the relationship between t, the time he walks in hours, and d, the distance he walks in miles. Which of the graph best describes the relationship?
The equation d=4t is a linear equation.
When t=1, d=4 X 1 =4
When t=2, d=4 X 2 =8
The correct graph that satisfies this pair is A (as seen in the diagram)
Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒

Equation [2] ⇒

We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;

and

, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either

or

the subject:


Then we substitute

into Equation [2]






Now we know the value of

which is

, substitute this value into

we have

Answer:
Numbers of books = 13
Numbers of CDs = 7
S = R + 3t - 5/2
multiply the r by the 2 and transfer -6t and 5 over to the left side which makes them +6t and -5, then divide the whole left side by 2 which gives you s
The right answer is:
<em>area B = area C</em>
We can solve this problem by using Kepler's laws of planetary motion. There are three Kepler's laws. In this exercise, we need to use the second law. According to this law,<em> a line segment joining a planet and the sun sweeps out equals areas during equals intervals of time. </em>So, a certain planet sweeps out an <em>area B </em>from the point <em>P3 </em>to <em>P4</em> in an interval of time <em>t. </em>On the other hand, for the same interval of time <em>t, </em>the planet sweeps out an <em>area C </em>from point <em>P4</em> to <em>P5, </em>that is equal to the previous area according to second kepler's law.