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nexus9112 [7]
2 years ago
13

A company has two office buildings that hold 30,000 employees. Their headquarters contains 14 times as many employees as their o

verseas branch. Therefore, their headquarters contains __?__ employees.
Mathematics
2 answers:
VikaD [51]2 years ago
7 0

Answer:

Their headquarters contains <u>420000</u> employees.

Step-by-step explanation:

The company has two office buildings which hold 30,000 employees.

The headquarters contains 14 times as many employees as the overseas branch.

Therefore, the number of employees in the headquarters is:

14 * 30000 = 420000 employees

Their headquarters contains 420000 employees.

Guest
1 year ago
I think we are to assume that one of the buildings is the headquarters and the other is the overseas branch, so this would be incorrect. We have to spit the number of employees for the 2 buildings. One will have 14 times more than the other. The answer should be under 30000.
Guest1 year ago
0 0

14x + x = 30,000
15x=30,000
x=2,000
14x= 14(2,000)= 28,000

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katovenus [111]

Answer:

She subtracted the coefficients instead of dividing them

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The California State University (CSU) system consists of 23 campuses, from San Diego State in the south to Humboldt State near t
miv72 [106K]

Answer:

For this case since since they not want to differentiate between the campuses, so is good to use a simple random sampling or SRS, that is a procedure in order to select a sample of size n from a population of size N known, and each element of the population have the sample probability of being selected p=\frac{1}{N}

So then the administrator can select a random sample of n students from all the campuses from the CSU University and obtain the distance from hometwon to campuses for the selected sample and then calculate the average and use this to inference.

Other possibility is use a systematic random sampling for example they can define a random number k and they can select 1 student each k individuals and then create a random sample of size n and calculate the average for this in order to do inference.

The convenience sampling is not too useful since is not a probabilistic method.

Step-by-step explanation:

For this case we can clasify this study as an enumerative study and inferential since they want to identify the average distance between the hometowns of students and their campuses.

For this case the sampling frame represent all the 23 campuses, and is known for the researcher,

For this case since since they not want to differentiate between the campuses, so is good to use a simple random sampling or SRS, that is a procedure in order to select a sample of size n from a population of size N known, and each element of the population have the sample probability of being selected p=\frac{1}{N}

So then the administrator can select a random sample of n students from all the campuses from the CSU University and obtain the distance from hometwon to campuses for the selected sample and then calculate the average and use this to inference.

Other possibility is use a systematic random sampling for example they can define a random number k and they can select 1 student each k individuals and then create a random sample of size n and calculate the average for this in order to do inference.

The convenience sampling is not too useful since is not a probabilistic method.

6 0
2 years ago
The closing price (in dollars) per share of stock of tempco electronics on the tth day it was traded is approximated by p(t) = 2
Vaselesa [24]

solution:

The closing price (in dollars) per share of stock of Tempco Electronics on the tth day it was  

traded is approximated by  

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15 (0 ≤ t ≤ 24)  

where t = 0 corresponds to the time the stock was first listed on a major stock exchange.  

What was the rate of change of the stock's price at the close of the 15th day of trading?  

P'(t) = 12(cos πt/30) - 6 (cos πt/15) + 4(cos πt/10) - 3(cos 2πt/15)  

t = 15  

P'(t) = 12(cos 15π/30) - 6 (cos 15π/15) + 4(cos 15π/10) - 3(cos 30π/15)  

P'(t) = 12(cos π/2) - 6 (cos π) + 4(cos 3π/2) - 3(cos 2π)  

P'(t) = 12(0) - 6(-1) + 4(0) - 3(1) = 6 - 3  

P'(t) = $3 per day RATE OF CHANGE  

the closing price on that day

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15  

t = 15  

P(t) = 20 + 12 sin 15π/30 − 6 sin 15π/15 + 4 sin 15π/10 − 3 sin 30πt/15  

P(t) = 20 + 12 sin π/2 − 6 sin π + 4 sin 3π/2 − 3 sin 2π  

P(t) = 20 + 12(1) − 6(0) + 4(-1) − 3(0) = 20 + 12 - 0 - 4 - 0 = 20 + 12 - 4  

P(t) = $28 per share close price



4 0
2 years ago
Explain how to estimate 368+231 in two different ways
Dennis_Churaev [7]
400+200 or add 368+231= 599 and you round your answer, woulb be 600
6 0
2 years ago
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Alliance Cannery has two assembly lines. One produces 24 cans of fruit per minute; the other produces 64 cans of vegetables per
sergey [27]
Let
x----------------------- > number of <span>cans of fruit-----------------> 24 per minute
</span>y----------------------- > number of cans of vegetables-------> 64 per minute
<span>z----------------------- > number of cans of food per minute
t----------------------- > time in minutes

z=(x+y)*t
z=(24+64)*t--------------- > 88t
z=88t---------------------------------- > this is the equation required
we know that z=384
then 
</span>384=88t------------- > t=4.36 minutes
5 0
2 years ago
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