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2 years ago

Use f(x)=1/2x and f^-1(x)=2x to solve the problems f^1(-2), f(-4), f(f^-1(-2)?

Mathematics

2 answers:

neonofarm [45]2 years ago

8 0

F^1(-2) = 2(-2) = -4
f(-4) = 1/2 * -4 = -2

f(f^-1(x)) = x so answer is -2

Goshia [24]2 years ago

8 0

Answer: The required values are

$f^{-1}(-2)=-4,~~f(-4)=-2,~~f(f^{-1}(-2))=-2.$

Step-by-step explanation: We are given a function f(x) and its inverse as follows :

$f(x)=\dfrac{1}{2}x,\\\\\\f^{-1}(x)=2x.$

We are to find the values of $f^{-1}(x),~f(-4),~f(f^{-1}(-2)).$

The values are evaluated in the following manner :

$f^{-1}(-2)=2\times(-2)=-4,\\\\\\f(-4)=\dfrac{1}{2}\times(-4)=-2,\\\\\\f(f^{-1}(-2))=f(-4)=-2.$

Thus, the required values are

$f^{-1}(-2)=-4,~~f(-4)=-2,~~f(f^{-1}(-2))=-2.$

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meriva

Answer:
sin F = 4/5
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tan D = 3/4

Explanation:
First, we have sin an angle = 4/5
In a right-angled triangle:
sin theta = opposite / hypotenuse
This means that in triangle DFE:
The hypotenuse = 5 units
one of the sides = 4 units
Use Pythagorean theorem to get the other side as follows:
hypotenuse^2 = side1^2 + side2^
25^2 = 4^2 + side2^2
side2^2 = 9
The second side of the triangle = 3 units

The special trig functions are as follows:
sin theta = opposite / hypotenuse
cos theta = adjacent / hypotenuse
tan theta = opposite / adjacent
From the attached figure and based on the calculations above:
sin F = 4/5
cos F = 3/5
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kodGreya [7K]

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Step-by-step explanation:

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