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Ahat [919]
1 year ago
15

Estimate the volume of the solid that lies below the surface z = xy and above the following rectangle. R = (x, y) | 2 ≤ x ≤ 8, 6

≤ y ≤ 10 (a) Use a Riemann sum with m = 3, n = 2, and take the sample point to be the upper right corner of each square. (b) Use the Midpoint Rule to estimate the volume of the solid.

Mathematics
1 answer:
Marianna [84]1 year ago
8 0

See attached picture:

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A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.
qwelly [4]
A = 0.9 o 
<span>so, </span>
<span>o = a/0.9 = 1.111a </span>
<span>so, the orange is 11% heavier than the apple. 

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6 0
2 years ago
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Which of the following is a key property of the quadratic parent function?
Mars2501 [29]

Answer: B

Step-by-step explanation:

Quadratic parent function is y=x^2  which means the vertex is the origin because if you input 0 into the function you will get an output of zero. (0,0) is the origin which is where the graph intersect.

6 0
2 years ago
The sides of a square are three to the power of two sevenths inches long. What is the area of the square? (
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Answer:

Step-by-step explanation:

The side of the square = 3^2/7

Use the law of exponents . If the power is a fraction, that means it is

3^2/7 = 3^2 x 1/7 = 7√9

To find the area you multiply this by itself.

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Hope this helps

8 0
2 years ago
A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will
enyata [817]

Answer:

a) Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

4 0
2 years ago
Simplify the expression to a form in which 2 is raised to a single integer power. fraction numerator open parentheses 2 to the p
anzhelika [568]

Answer:

2^27

Step-by-step explanation:

Given the following expression:

[(2^10)^3 x (2^-10)] ÷ 2^-7

This can be easily simplified. Let us simplify the numerator first. To do that, we have

(2^10)^3 making use of the power rule of indices that says:

(A^a)^b = A^ab where a and b are powers, we have:

2^(10x3) = 2^30

Therefore the numerator becomes:

2^30 x 2^-10. Also making use of the multiplication rule that says:

A^a x A^b = A^(a + b), we have

2^30 x 2^-10 = 2^(30 – 10) = 2^20.

Now we have:

(2^20) ÷ (2^-7)

To simplify this, we need the division rule of indices which says:

A^a ÷ A^b = A^(a – b)

Therefore we have:

(2^20) ÷ (2^-7) = 2^[20 – (–7)] = 2^(20+7) = 2^27

5 0
1 year ago
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