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PIT_PIT [208]
2 years ago
5

Here is the scale model of a fountain at a museum the scale is 1:30 how many boulders are in the real fountain

Mathematics
2 answers:
wlad13 [49]2 years ago
6 0

Answer:

When we do a scale model of something (like a building, a house, or whatever) al the properties of the original thing must also be in the model.

So for example, you want to do a model of a house, and in the backyard of the house there are 4 trees, then in the model of the house you also need to put 4 trees in the backyard (indifferent of the scale of the model).

Then the number of boulders in the really fountain should be the same as the number of boulders in the scale model of the fountain.

MissTica2 years ago
3 0

Answer:

c. 10

Step-by-step explanation:

i just took the test

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The graph below represents the possible dimensions of a horse corral to be constructed behind a barn. The width of the corral is
alexira [117]

Answer:

I think its C

Step-by-step explanation:

6 0
1 year ago
To solve 16x18, I double and halve?
Goshia [24]
To solve 16x18, you may split it up into a smaller increment you understand. Like 16x2, which equals 32. (18/2 is 9) multiply 32 by 9. you get your answer 288.
8 0
1 year ago
The perimeter of a triangle equals 8 inches. Two of its sides are equal and each of them is 1.3 inches bigger than the third sid
mafiozo [28]
Let's call the lengths of our two types of sides <em />x and y.

The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus, x = y + 1.3.

Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
(y + 1.3) + (y + 1.3) + y = 3y + 2.6 = 8

Now, let's solve for y.
3y + 2.6 = 8
3y = 5.4
y = 1.8

Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is y + 1.3 = 1.8 + 1.3 = \boxed{3.1} inches and the length of our smaller side is simply \boxed{1.8} inches.

To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
5 0
2 years ago
A scientist had a bottle that contains 56.6 ML of a solution. she used 3.2 ML of the solution for an experiment then she poured
hjlf
1. 56.6 - 3.2 = 53.4
2. 53.4 divided by 2 = 26.7
3. 26.7 - 6 = 20.7
Answer: 20.7 mL
3 0
2 years ago
An unloaded truck and trailer, with the driver aboard, weighs 30{,}00030,00030, comma, 000 pounds. When fully loaded, the truck
kari74 [83]

Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

\text{Average weight of one pallet of cargo}=1130.769230769

\text{Average weight of one pallet of cargo}\approx 1131

Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.

3 0
1 year ago
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