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PIT_PIT [208]
2 years ago
5

Here is the scale model of a fountain at a museum the scale is 1:30 how many boulders are in the real fountain

Mathematics
2 answers:
wlad13 [49]2 years ago
6 0

Answer:

When we do a scale model of something (like a building, a house, or whatever) al the properties of the original thing must also be in the model.

So for example, you want to do a model of a house, and in the backyard of the house there are 4 trees, then in the model of the house you also need to put 4 trees in the backyard (indifferent of the scale of the model).

Then the number of boulders in the really fountain should be the same as the number of boulders in the scale model of the fountain.

MissTica2 years ago
3 0

Answer:

c. 10

Step-by-step explanation:

i just took the test

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Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when
valentina_108 [34]

Solution:

f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5

We have to find the remainder when f(x) is divided by x^2-1.

x²-1=0

x=\pm1

f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13

So, remainder is 13 and -13.

5 0
1 year ago
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Royce is folding a piece of paper to make an origami figure. Each time he folds the paper, the thickness of the paper is doubled
Alisiya [41]
The input value is the number of times you fold it. The input value is also known as the x-value. 
The output value is its thickness. The output value is the y-value.

When you don't fold it all, the thickness will remain the same, which is 2. The ordered pair would be (0, 2).

When you fold it once, the thickness will double from 2 to 4. The ordered pair would be (1,4).

When you fold it a second time, the thickness will double from 4 to 8. The ordered pair would be (2,8).

Fold it one more time, and the thickness will be 16. The ordered pair is (3,16)

Fold it the fourth time, and the thickness doubles. 16 x 2 = 32 The ordered pair is (4, 32)

Fold it the fifth time, and the thickness goes from 32 to 64. The ordered pair is (5,64)

The ordered pairs would be:
(0,2)
(1,4)
(2,8)
(3,16)
(4,32)
(5,64)
(6,128)
(7,256)
and so on :P

The question asks for 6 ordered pairs, so I bolded the first six.

Now, the equation for this would be y = 2^{(x+1)}

If we graph that, and we do the vertical line test, then we know this is a function.

It is a function because each x-value has a different y-value. There are no y-values that have the same x-values.

<span>I have attached the graph of that line.</span>

6 0
2 years ago
Fiona and her friends went to a smoothie shop. They ordered three strawberry smoothies and two protein shakes for a total of $24
yulyashka [42]
5.25 dollars for the protein shake and 4.5 for the strawberry smoothies
5 0
2 years ago
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The density of gold is 19.3 g/cm3. A weight of 1 ounce is equivalent to a mass of about 28.35 g. Which of these is closest to th
cluponka [151]

Answer: The side length of the cube is 2.27cm

Step-by-step explanation:

The options are not given, then let's solve this in a general way.

We know that the density of gold is 19.3g/cm^3.

We also know that 1 oz = 28.35g.

And we know the relation:

Density = mass/volume.

Now, let's find the volume of 8 ounces of gold.

First, let's rewrite the density changing the units, from grams to ounces.

We know that:

1 oz = 28.35g

(1 oz/28.35g) = 1.

Then if we multiply the density by this ( that is equal to 1) we can change the units and leave the actual quantity invariant.

d =  19.3g/cm^3 =  19.3g/cm^3*(1 oz/28.35g) = 0.68 oz/cm^3

Now let's use the equation for the density, knowing this time that the mass is 8 ounces.

0.68 oz/cm^3 = mass/volume = 8oz/V

Let's find the value of V

0.68 oz/cm^3 = 8oz/V

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Now, we know that this is a cube.

Remember that the volume of a cube of side length L is:

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8 0
1 year ago
Bob's bill for dinner at surefire steak house was $45. In addition he piad 5°\° of the bill in tax and he left a tip for 15°\° o
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Answer:

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Step-by-step explanation:

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Second

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Fourth

45+2.25+6.75

5 0
1 year ago
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