Ask question

Ask question

All categories

2 years ago

13

CD is a perpendicular bisector of . Which of the following could be the slopes of the two lines if plotted on a coordinate grid?

A 1/2 and 2 B 4 and -4 C 1/3 and 1/3 D -7 and 1/7

1 answer:

NISA [10]2 years ago

8 0

Step-by-step explanation:

A is the correct answer of this question

You might be interested in

11x+5x-65x=-36<br> Porfavor ayuda

abruzzese [7]

If you need this simplified $x= \frac{36}{49}$

5 0

1 year ago

(n) ________ is a variable that affects both variables of interest and may falsely give the impression of a cause-and-effect rel

gtnhenbr [62]

Answer: CONFOUNDING VARIABLES

Step-by-step explanation: Confounding variables are

unexpected external factor that affects both variables of interest, confounding variables usually gives the false impression that changes in one variable leads to changes in the other variable, when, in Actual, it is the external factor that caused the change being investigated. Confounding variables usually leads to wrong conclusions during research and experiments and are capable of causing biased outcomes when the real cause and effect relationship is not determined.

4 0

2 years ago

Company A charges $331.35 per week for a compact car with unlimited miles. Company B charges $175 per week plus $0.53 per mile,

Vladimir [108]

Answer:

Company A is a better deal than Company B for the number of miles greater than 295 miles

Step-by-step explanation:

Let

y ----> the charge per week in dollars

x ----> the number of miles

we have

<em>Company A</em>

$y=331.35$ -----> equation A

<em>Company B</em>

$y=0.53x+175$ -----> equation B

Solve the system by substitution

Equate equation A and equation B and solve for x

$331.35=0.53x+175$

$0.53x=331.35-175\\0.53x=156.35\\x=295\ mi$

For x=295 miles the charge in Company A and Company B is the same

therefore

Company A is a better deal than Company B for the number of miles greater than 295 miles

5 0

2 years ago

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

lisov135 [29]

Answer:

A. StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction

Step-by-step explanation:

Given:

(2x + 5) / (x² - 3x) - (3x + 5) / (x³ - 9x) - (x + 1) / x² - 9

Factor the denominators

(2x + 5) / x(x - 3) - (3x + 5) / x(x - 3)(x + 3) - (x + 1) / (x - 3)(x + 3)

Lowest common multiple of the 3 fractions is x(x - 3)(x + 3)

= (2x+5)(x+3) - (3x + 5) - (x + 1)x / x(x - 3)(x + 3)

= (2x²+6x+5x+15) - (3x + 5) - (x² + x) / x(x - 3)(x + 3)

= 2x² + 11x + 15 - 3x - 5 - x² - x / x(x - 3)(x + 3)

= x² + 7x + 10 / x(x - 3)(x + 3)

Solve the numerator.

Solve the quadratic expression by finding two numbers whose product is 10 and sum is 7

The numbers are 5 and 2

= x² + 5x + 2x + 10 / x(x - 3)(x + 3)

= x(x + 5) + 2(x + 5) / x(x - 3)(x + 3)

= (x + 5)(x + 2) / x(x - 3)(x + 3)

A. StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction

Recall,

x(x - 3)(x + 3) is a factor of x³ - 8x

A. StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction

(x + 5)(x + 2) / x³ - 9x

B. StartFraction (x + 5) (x + 4) Over x cubed minus 9 x EndFraction

(x + 5)(x + 4) / x³ - 9x

C. StartFraction negative 2 x + 11 Over x cubed minus 12 x minus 9 EndFraction

2x + 11 / x³ - 12x - 9

D. StartFraction 3 (x + 2) Over x squared minus 3 x EndFraction

3(x + 2) / x² - 3x

3 0

1 year ago

Darcie wants to crochet a minimum of 3 blankets. Darcie crochets at a rate of 1/15 of a blanket a day. She has 60 days until she

NNADVOKAT [17]

Answer:

The inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal can be given as:

$s\leq 15$

Step-by-step explanation:

The complete question is:

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

Given:

Darcie wants to crochet a minimum of 3 blankets to donate.

Rate at which she crochet = $\frac{1}{15}$ of a blanket per day.

Maximum number of days she has = 60.

To find the number of days Dancie can skip out of 60 days and still reach her goal.

Let $s$ represent the number of days she can skip.

Number of days left to crochet = $(60-s)$ days

At rate of $\frac{1}{15}$ of a blanket per day, number of blankets Dancie can corchet in $(60-s)$ days can be given as :

⇒ $\frac{1}{15}(60-s)$

Simplifying using distribution.

⇒ $(\frac{1}{15}.60)-(\frac{1}{15}.s)$

⇒ $4-\frac{s}{15}$

Dancie needs to crochet a minimum of 3 blankets to reach her goal.

Thus, the inequality can be given as:

$4-\frac{s}{15}\geq 3$

Solving the inequality for $s$

Subtracting 4 both sides.

$4-4-\frac{s}{15}\geq 3-4$

$-\frac{s}{15}\geq -1$

Multiplying both sides by -15.

$-15(-\frac{s}{15})\leq -15(-1)$ [On multiplying by a negative number the sign of inequality reverse]

∴ $s\leq 15$

Thus, Dancie can skip a maximum of 15 days.

5 0

2 years ago