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2 years ago

13

CD is a perpendicular bisector of . Which of the following could be the slopes of the two lines if plotted on a coordinate grid?

A 1/2 and 2 B 4 and -4 C 1/3 and 1/3 D -7 and 1/7

1 answer:

NISA [10]2 years ago

8 0

Step-by-step explanation:

A is the correct answer of this question

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A weatherman collected data on snow accumulation. A line of best fit was computed. The equation for the line is: y = 1.5x + 0.12

SVETLANKA909090 [29]

Answer:

5x-12=42 over 3 subtract that and you will get 1

Step-by-step explanation:

8 0

2 years ago

A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na

Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply<em> the average speed formula</em>, which is defined by:

$v=\frac{d}{t}$

where d is the total distance traveled and t is the total time needed.

$d=\frac{4.00}{1.75}=2.29$ km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0

1 year ago

The green goober a wildly unpopular hero mixes 3 L of yellow paint was 5 L of blue plate to make a leader is a special green pai

Butoxors [25]

Answer:

<u>The equation can be y = 3b/5 or b = 5y/3</u>

Correct statement and question:

The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of special green paint for his costume.

Write an equation that relates the amounts (in liters) of yellow paint (y) and blue paint (b) needed to make the Green Goober's special green paint.

Source:

Previous question that can be found at brainly

Step-by-step explanation:

Let y to be the amount of liters of yellow paint needed to make the Green Goober's special green paint.

Let b to be the amount of liters of blue paint needed to make the Green Goober's special green paint.

We know that:

y:b = 3:5

Therefore,

5y = 3b, dividing by 5 at both sides we have:

y = 3b/5

And also dividing by 3 at both sides we have:

<u>b = 5y/3</u>

Both equations relate the amounts (in liters) of yellow paint and blue paint needed to make the Green Goober's special green paint.

4 0

1 year ago

What is 2 divided 1 6/7 ? Please answer

Aliun [14]

If you would like to divide 2 by 1 6/7, you can do this using the following steps:

1 6/7 = 13/7

2 / 1 6/7 = 2 / 13/7 = 2/1 / 13/7 = 2/1 * 7/13 = 14/13 = 1 1/13

The correct result would be 1 1/13.

6 0

2 years ago

The swimming instructor has a list of 152 students who have signed up for swimming lessons. The swimming instructor can register

andrew-mc [135]

Answer:

2. 13

Step-by-step explanation:

The least number of classes need for all of the students to be registered in a class is 13 since you want all of the stuednts to be registered so no one should be left out. If we do 12*12 (12 students in each class and there are 12 classes), that would only let 144 students take the swimming classes and 8 students would be left out. We don't want that though since we want all of the students to be registered. So let's go to 12*13 (12 students in each class and there are 13 classes), that would let 156 students take the swimming class. 156>152 so therefore, 13 classes would allow for all 152 students to be registered and it is the least number of classes needed for all the students to be registered in a class (plus you would have 4 seats left for anyone who wants to register in the future but the remainder doesn't matter).

6 0

2 years ago