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ASHA 777 [7]
1 year ago
6

At a cookout, Mrs. Crawford makes 8/9 pound of chicken, plus 1 pound for each guest. Is the relationship between the number of g

uests and pounds of chicken proportional?
Mathematics
2 answers:
Julli [10]1 year ago
6 0

Answer:

No, it is not a proportional relation.

Step-by-step explanation:

Let x represents the number of guest and y represents the number of pounds of chicken made,

Given,

The number of pounds of chicken for each guest = 1,

So, the number of pounds for x guests = x,

Also, the number of pounds already made = \frac{8}{9}

Thus, the total pounds of chicken,

y=\frac{8}{9}+x

Since, a relation is called proportional if the variables are directly proportional,

That is, the line obtained by the relation passes through the origin,

Since, if x = 0, y = 0,

0=\frac{8}{9}+0

∴ Line y=\frac{8}{9}+x does not pass through the origin.

Hence, given relation is not proportional.

erma4kov [3.2K]1 year ago
3 0
No, this rel. is not proportional because of the addition involved ("plus 1 lb for each guest").

A proportional rel. features mult. only.

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The probability is 10/12. If you need it as a decimal, it should be about 8.3%
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The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If
frutty [35]
For this case we have the following equation:
 w = 0.9* \sqrt{E}
 Where,
 w: The weight of a spring in pounds
 E: the energy stored by the spring in joules.
 Substituting values we have:
 w = 0.9* \sqrt{12}
 Making the corresponding calculation:
 w=3.12
 Answer:
 
the approximate weight of the spring in pounds is:
 
w=3.12
4 0
1 year ago
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A randomized study compared two different systems for tracking baggage at an airport. The treatment group using System A reporte
Natasha2012 [34]

Answer:

D. The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

Step-by-step explanation:

The treatment group using System A reported a mean of 18.5 lost bags per day. The treatment group using System B reported a mean of 16.6 lost bags per day.

The best conclusion that can be made is - The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

As we know, in statistics, nothing happens by chance. So, this option is correct.

8 0
2 years ago
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What value for c will make the expression a perfect square trinomial? x2 – 7x + c negative StartFraction 49 Over 4 EndFraction n
puteri [66]

Answer: c=\frac{49}{4}

Step-by-step explanation:

You can find the value of "c" that will make it a perfect square trinomial by Completing the square.

Given the following expression provided in the exercise:

x^2 - 7x + c

You can notice that it is written in this form:

ax^2-bx+c

Then, you can identify that the coefficient "b" is:

 b=-7

Since to complete the square you must add and subtract the half of square of coefficient "b", you can conclude that:

c=(\frac{b}{2})^2

Therefore, substituting "b" into c=(\frac{b}{2})^2, you get:

c=(\frac{-7}{2})^2\\\\c=\frac{49}{4}

6 0
2 years ago
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In a study in Scotland (as reported by Devlin 2009), researchers left a total of 320 wallets around Edinburgh, as though the wal
Ann [662]

Answer:

a) The observed proportion of wallets that were returned

  p = 0.45625

b) <em> 95% of confidence intervals for Population proportion</em>

<em>  0.40168  , 0.51082)</em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

a)

Given data the  researchers left a total of 320 wallets around Edinburgh, as though the wallets were lost. Each contained contact information including an address. Of the wallets, 146 were returned by the people who found them

Given sample size 'n' = 320

  Given data          'x ' = 146

<em>Sample proportion </em>

              p = \frac{x}{n}

             p = \frac{x}{n} = \frac{146}{320} = 0.45625

<u><em>Step(ii)</em></u>:-

b)<em> </em><u><em>95% of confidence intervals for Population proportion</em></u>

Level of significance = 95% or 0.05%

Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96

<em>95% of confidence intervals for Population proportion are determined by</em>

<em></em>(p - Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} } , p + Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} })<em></em>

<em></em>(0.45625 - 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} } , 0.45625 + 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} })<em></em>

<em>(0.45625 - 0.05457 , 0.45625 + 0.05457)</em>

<em>(   0.40168  , 0.51082) </em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

7 0
1 year ago
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