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Butoxors [25]
1 year ago
9

a dance club spent $922 on 40 items.The item include some hats and pairs of shoes.Each hat cost $19 and each pair of shoes cost

$25.How many pairs of shoes did the dance club buy?​
Mathematics
1 answer:
Sergio039 [100]1 year ago
4 0

1. H+S=40

2. 19H+25S=922

From 1,

19H+19S=760

Subtract this from 2 to eliminate H,

19H+25S-19H-19S=922-760

6S=162

Solve for S, then use either equation to solve for H.

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The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

5 0
2 years ago
An accident at an oil drilling platform is causing a circular-shaped oil slick to form. The volume of the oil slick is roughly g
Basile [38]

Answer:

V(t)=0.0112\pi t^{2}

Step-by-step explanation:

we have

V(r)=0.07\pi r^{2} -----> equation A

r(t)=0.4t -----> equation B

To find out (V of r)(t) substitute equation B in equation A

V(r(t))=V(t)

V(t)=0.07\pi (0.4t)^{2}

V(t)=0.07\pi (0.16)t^{2}

V(t)=0.0112\pi t^{2}

3 0
1 year ago
Malika charges $7.20 per hour for babysitting. She babysits 4 hours each week. She spends $10 per week and puts the rest of her
Juliette [100K]
$7.20        $28.8        $18.8        $225.6        $225.6
        4        $10              12                   .25       $56.4
X___       -_____         X____      X_____    +_____
$28.8       $18.8          225.6          $56.4        $282

You multiply $7.20 by the 4 hours she's working and you'll get $28.80. Then you would subtract the $10 from your answer and get $18.80. Then you'd multiply $18.80 by 12 for the mouths she's working and get $225.60. Next you multiply $225.60 by .25 from the grandparents and get $56.40. Finally you add $225.60 to $56.40 and get $282 in her savings account.
5 0
1 year ago
Solve<br> E=Mc2, M=3,C=6
Dmitry [639]

You substitute M for 3 and C for 6. So you get E = (3)(6)(2) which equals 36.

6 0
1 year ago
Read 2 more answers
A card player selects a playing card from a well-shuffled deck of standard playing cards and sees if the card is a red card or n
dmitriy555 [2]

Answer:

A

Step-by-step explanation:

there could be no red cards inside

8 0
2 years ago
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