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il63 [147K]
2 years ago
10

Se tiene una pirámide regular cuadrangular cuyas caras laterales forman con la base un angulo que mide 53º y el area de la super

ficie lateral es 60 ¿cuanto mide la altura?
Mathematics
1 answer:
SIZIF [17.4K]2 years ago
8 0

Answer:

La altura de la pirámide es de 8.14 unidades.

Step-by-step explanation:

Hay una pirámide cuadrangular regular cuyas caras laterales forman un ángulo que mide 53º con la base y el área de la superficie lateral es 60. ¿Qué altura tiene?

Dado que el área de superficie lateral = 60

Tenemos

Área del triángulo equilátero = (√3 / 4) × a²

 (√3 / 4) × a² = 60

a² = 60 / (√3 / 4) = 80 · √3

a = √ (80 · √3) = 11.77 unidades

La altura inclinada = Altura de la superficie inclinada = a × sin (60) = 11.77 × sin (60)

La altura inclinada = 11.77 × sin (60) = 10.194 unidades

La altura de la pirámide = Altura inclinada × sin (ángulo de caras laterales con la base)

La altura de la pirámide = 10.194 × sin (53) = 8.14 unidades.

La altura de la pirámide = 8.14 unidades.

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Answer:

  • y=250x+4000
  • y=400x+400

Step-by-step explanation:

Given that:

  • x represents the number of months of ownership; and
  • y represents the total paid for the car after ‘x' months.

<u>First Option (Leasing)</u>

250x - y + 4000 = 0

Expressing the equation in the Slope-Intercept Form y=mx+b, we have:

y=250x+4000

<u>Second Option (Financing)</u>

$400 for 0 months of ownership, (0,400), and $4400 for 10 months of ownership, (10, 4400).

First, we determine the slope of the line joining (0,400) and (10,4400)

Slope, m= \dfrac{4400-400}{10-0}= \dfrac{4000}{10}=400

We have:

y=400x+b

When y=400, x=0

400=400(0)+b

b=400

Therefore, the Slope-Intercept Form of the second option is:

y=400x+400

<u>Significance</u>

  • In the first option, there is a down payment of $4000 and a monthly payment of $250.
  • In the second option, there is a down payment of $400 and a monthly payment of $400.

<u>Part B</u>

We notice from the graph that after 24 months, the cost for leasing and financing becomes the same ($10,000). Therefore, a consumer will be better off financing since the downpayment for leasing is higher.

<u>i.e </u>

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4 0
2 years ago
In a sample of 100 steel canisters, the mean wall thickness was 8.1 mm with a standard deviation of 0.5 mm. Someone says that th
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Answer:

This statement can be made with a level of confidence of 97.72%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.1 mm

Standard Deviation, σ = 0.5 mm

Sample size, n = 100

We are given that the distribution of thickness is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.5}{\sqrt{100}} = 0.05

P(mean thickness is less than 8.2 mm)

P(x < 8.2)

P( x < 8.2)\\\\ = P( z < \displaystyle\frac{8.2 - 8.1}{0.05})\\\\ = P(z < 2)

Calculation the value from standard normal z table, we have,  

P(x < 8.2) =0.9772 = 97.72\%

This statement can be made with a level of confidence of 97.72%.

8 0
2 years ago
Michael draws a rectangle Alexis thought it might be a square what would be true of the diagonals if the rectangle is also a squ
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The diagonals would be perpendicular (intersect at a 90* angle)
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The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

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(b) between 5 and 10 minutes

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Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

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x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

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x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

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x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

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One possible inequality would be

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6 0
2 years ago
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