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Oksanka [162]
1 year ago
7

A man is in a boat that is floating 175 feet from the base of a 200 foot cliff. What is the angle of depression between the clif

f and the boat?
Mathematics
1 answer:
LUCKY_DIMON [66]1 year ago
8 0

Answer:

The of depression between the cliff and the boat is 48.74 degrees.

Step-by-step explanation:

We have,

Height of the cliff is 200 foot

Distance of boat from the cliff is 175 feet

It is required to find the angle of depression between the cliff and the boat.

Here, 200 foot is perpendicular distance and 175 is base.

Using trigonometry :

\tan\theta=\dfrac{P}{B}\\\\\tan\theta=\dfrac{200}{175}\\\\\theta=\tan^{-1}(1.14)\\\\\theta=48.74^{\circ}

So, the of depression between the cliff and the boat is 48.74 degrees.

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Novay_Z [31]

Answer:

Step-by-step explanation:

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(y=-25.31428571x+1000.285714

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now, lets use computer:

y=-25.31(543)+1000.3

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round to the biggest whole number )

this doesn't really work, so I will put 1999, 2000, 2001, 2002, 2003, 2004 instead of 0, 1, 2, 3, 4, 5 and do the same thing

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2 years ago
Charlie wants to order lunch for his friends. He'll order 5 sandwiches and a $3 kid's meal for his little brother. Charlie has $
Dominik [7]
Inequality:
5x - 3 ≤ 28

Answer:
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8 0
1 year ago
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How many liters of wine can be held in a wine barrel whose capacity is 28.0 gal? 1 gal = 4 qt = 3.7854 l?
wel

Answer:

105.9912 liters of wine can be held in a wine barrel whose capacity is 28.0 gal.

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal.

Let x be the liters of wine can be held in a wine barrel whose capacity is 28.0 gal.

Given that:

1 gal = 3.7854 l

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by definition of proportions;

\frac{1}{3.7854} =\frac{28}{x}

By cross multiply we get;

x = 28 \times 3.7854 = 105.9912 liters

Therefore, 105.9912 liters of wine can be held in a wine barrel whose capacity is 28.0 gal.

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In ADEF, f = 610 inches, e = 590 inches and ZE=70°. Find all possible values of ZF,
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Answer:

"76°" is the appropriate solution.

Step-by-step explanation:

Please find attachment of the diagram according to the given query.

The given values are:

In ΔDEF,

f = 610 inches

e = 590

∠E = 70°

∠F = ?

By using the law of sines, we get

⇒  \frac{Sin E}{e} =\frac{Sin  F}{f}

On substituting the values, we get

⇒  \frac{Sin70^{\circ}}{590} =\frac{SinF}{610}

On applying cross multiplication, we get

⇒   SinF=\frac{610\times Sin 70^{\circ}}{590}

On substituting the values, we get

⇒            =\frac{61\times 0.95969262}{59}

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⇒            =0.971546608

now,

⇒  F=Sin^{-1}(0.971546608)

⇒      =76^{\circ}

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Wouldnt it be four? id its 1/4

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