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ehidna [41]
2 years ago
9

Mr. Lim and Mr. Tay had $31 090 at first.Mr. Lim donated $2390 of his money and Mr. Tay spent half of his money on a holiday tri

p. As a result, Mr. Lim had 3 times as much money as Mr. Tay. How much money did Mr. Lim have at first?
Mathematics
2 answers:
hjlf2 years ago
7 0

Answer:

Mr.Lim had 19,610 dollars, and Mr.Tay had 1,1480 dollars at first.

andriy [413]2 years ago
3 0

Answer:

Mr.Lim had 19610 dollars, and Mr.Tay had 11480 dollars at first.

Step-by-step explanation:

You might be interested in
In 2003, the Accreditation Council for Graduate Medical Education (ACGME) implemented new rules limiting work hours for all resi
Alborosie

Answer:

80.67 hours

Step-by-step explanation:

Data provided in the question:

The number of weekly hours worked :

78 85 82 79 77 82 81 82 81 81 82 78

total number of observations = 12

Now,

Mean = (Sum of all the data values) ÷ (Total number of data values)

or

Mean = ( 78 + 85 + 82 + 79 + 77 + 82 + 81 + 82 + 81 + 81 + 82 + 78 ) ÷ 12

or

Mean = 968 ÷ 12

or Mean = 80.67 hours

8 0
2 years ago
A reporter for a large sports television network wants to determine if "homefield advantage" is dependent upon the sport. He col
Ne4ueva [31]

Answer:

with 0.10 level of significance the P-VALUE that would be used in the hypothesis claim is 0.05%

Step-by-step explanation:

In hypothesis testing in statistics, we can say that the p-value is a probability of obtaining test results when we assume that the null hypothesis is correct.

The p-value is the probability that the null hypothesis is true.

A p-value less than or equals to 0.05  is statistically significant. It shows strong evidence against the null hypothesis, meaning  there is less than a 5% probability the null is correct and clearly we can say that the results are random.

8 0
2 years ago
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
2 years ago
in germany, VAT is at 19% Jeremy buys a calculator in germny for €58.31 This price includes VAT Find the amount of VAT paid by
Len [333]

We can use this equation to solve this problem:

<span>t=p+<span>(p⋅r)</span></span>

Where:

t is the total price paid: 58.31 for this problem

p is the price before taxes: What we are solving for in this problem.

r is the tax or VAT rate: 19% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 19% can be written as <span>19100</span> or 0.19.

Substituting and solving for p gives:

<span>58.31=p+<span>(p⋅0.19)</span></span>

<span>58.31=1p+0.19p</span>

<span>58.31=<span>(1+0.19)</span>p</span>

<span>58.31=1.19p</span>

<span><span>58.311.19</span>=<span><span>1.19p</span>1.19</span></span>

<span>49=<span><span>1.19p</span>1.19</span></span>

<span>49=p</span>

<span>p=49</span>

Now, we can find how much the VAT was by taking 19% of 49:

<span>19%×49=0.19×49=9.31</span>

Another was to solve this is to subtract the price without the tax or VAT from the total price giving:

<span>58.31−49=<span>9.31</span></span>

4 0
2 years ago
Read 2 more answers
Kirsty counts the number of peas in a sample of pea pods
RoseWind [281]
Mode is most occurring

There is no mode for the peas as there is no score occurring more than once


Median is middle number

So cross of 4 and 5, and 7 and 8

Median is 6


Mean is average


4+5+6+7+8 divided by five


Mean is 6


5 0
2 years ago
Read 2 more answers
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