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liubo4ka [24]
2 years ago
9

jack puts 1/3 pound of birdseed into his feeder every time he fills it. how many can jack fill his bird feeder with 4 pounds of

birdseed?
Mathematics
1 answer:
Flura [38]2 years ago
4 0

Answer: Jack can fill his feeder 12 times with 4 pounds of birdseed.

Step-by-step explanation:

You need to analize the information given in the exercise, You know that every time Jack fills the feeder, he put \frac{1}{3} pounds into it.

Then, in order to solve this exercise, let "x" represents the number of times that Jack can fill his  feeder with 4 pounds of birdseed.

Keeping on mind the data provided in the exercise, you can set up de following proportion:

\frac{1}{\frac{1}{3}} = \frac{x}{4}

Finally, you must solve for "x" in order to find its value.

You get that this  is:

3= \frac{x}{4}\\\\(3)(4)=x\\\\x=12

Therefore, you can conclude that Jack can fill his feeder 12 times with 4 pounds of birdseed.

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For which of the following counts would a binomial probability model be reasonable? a. The number of traffic tickets written by
timama [110]

Answer:

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 assuming numbers (0,1,2,3,4,5,6,7,8,9) so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

The conditions to apply this distribution is that we have the parameters fixed n and p.

Let's analyze one by one the possible solutions:

a. The number of traffic tickets written by each police officer in a large city during one month.

False, the number of traffic tickets written by each police is not a fixed amount always, so then the value of n change and we can't apply a binomial model for this case.

b. The number of hearts in a hand of five cards dealt from a standard deck of 52 cards that has been thoroughly shuffled.

False, not all the hands of size 5 are equal and since we can't ensure this condition then the binomial model not apply for this case

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

d. The number of phone calls received in a one-hour period.

False, the number of phone calls change by the hour and is not always fixed so then we don't have a valu for n, and the binomial model not applies for this case.

e. All of the above.

False option C is correct.

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2 years ago
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Lorico [155]

Hope this is what you need

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2 years ago
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Jamal wants to construct a tangent line to circle O that passes through point M. He started by drawing a segment from point O to
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The next step in his construction would have to be constructing the line between point M and point G. This is now your tangent line to the circle O. Additionally, you can also construct another tangent line that also passes through point M!
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Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp
yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

H_0: \mu=2\\\\H_a:\mu< 2

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803

The degrees of freedom for this sample size are:

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This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

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Number of tickets sold on
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