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musickatia [10]
1 year ago
15

Global Airlines operates two types of jet planes: jumbo and ordinary. On jumbo jets, 25% of the passengers are on business while

on ordinary jets 30% of the passengers are on business. Of Global's air fleet, 40% of its capacity is provided on jumbo jets. (Hint: The 25% and 30% values are conditional probabilities stated as percentages.) What is the probability a randomly chosen business customer flying with Global is on a jumbo jet?
Mathematics
1 answer:
MArishka [77]1 year ago
8 0

Answer:

Answer:

The  probability is  P(J|B) =  0.36

Step-by-step explanation:

B =business

J=jumbo

Or =ordinary

From the question we are told that  

     The proportion of the passenger on business in the ordinary jet  is P(B| Or) =  0.25

     The proportion of the passenger on business in the jumbo jet  is  P(B|J)  =  0.30

     The  proportion of the passenger on jumbo jets is  P(j) = 0.40

      The   proportion of the passenger on ordinary jets is evaluated as

         1 - P(J) =  1- 0.40  =  0.60

According to  Bayer's theorem the probability a randomly chosen business customer flying with Global is on a jumbo jet is mathematically represented as

        P(J|B) =  \frac{P(J) *  P(B|J)}{P(J ) *  P(B|J) +  P(Or ) *  P(B|Or)}

substituting values

         P(J|B) =  \frac{ 0.4 *   0.25}{0.4 *  0.25 +  0.6 * 0.3}

         P(J|B) =  0.36

Step-by-step explanation:

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The manufacturer of a smart watch claims that individuals who pay attention to how many steps they take per day will inadvertent
goldenfox [79]

Here is the correct question.

The manufacturer of a smart watch claims that individuals who pay attention to how many steps they take per day will inadvertently take more steps per day than individuals who pay no attention to how many steps they take per day. To investigate this claim, the manufacturer conducts a study to estimate the difference in the mean number of steps taken by those that pay attention to how many steps they take per day and those that do not. To do so, 40 volunteers are recruited. Half of the volunteers are randomly assigned to receive a smart watch and are taught how to use it to track their steps. The other half of the volunteers are given a wristband to wear, but are not informed that the wristband is tracking their steps. The volunteers are monitored for 30 days. The mean and standard deviation of the number of steps taken per day are computed for each group. Here are the data:

                                           n                     \bar x                  S_x

Pay attention                    20                 10,244            1,580

Do not pay attention        20                 8.,648            2,350

Which of the following is a 99% confidence interval for the difference in the mean number of steps taken by all people like these that do and do not pay attention to the number of steps they take per day using df - 19 ?

(A)  \ 1596  \ \pm 2.861 \sqrt{ \dfrac{1580^2}{20} + \dfrac{2350^2}{20}}  \\  \\ \\ (B)  \ 1596  \ \pm 2.861 \sqrt{ \dfrac{1580^2}{20} - \dfrac{2350^2}{20}} \\ \\  \\ (C)  \ 1596   \pm 2.576  \sqrt{ \dfrac{1580^2}{20} + \dfrac{2350^2}{20}}  \\ \\  \\ (D) 1596 \pm 2.576 ( \dfrac{1580^2}{\sqrt{20}} + \dfrac{2350^2}{\sqrt{20}}) \\ \\ \\ (E) 1596 \pm 2.576 ( \dfrac{1580^2}{\sqrt{20}} -  \dfrac{2350^2}{\sqrt{20}})

Answer:

\mathbf{(A)  \ 1596  \ \pm 2.861 \sqrt{ \dfrac{1580^2}{20} + \dfrac{2350^2}{20}}}

Step-by-step explanation:

Given that :

significance level \alpha = \mathbf{0.01}

From the Given data;

Using Excel with the function : TINV(0.01,19);

Critical value t* = 2.861

The margin of error can now be represented by the illustration:

Margin of error = t^* \sqrt{ \dfrac {s_1 ^2}{n_1} + \dfrac {s_2 ^2}{n_2}

Lower Limit =  (\bar x_1 - \bar x_2)- (Margin \ of \ error)

Upper Limit =  (\bar x_1 - \bar x_2)+ (Margin \ of \ error)

Thus; the confidence interval for the difference in the mean number of steps taken by all people like these that do and do not pay attention to the number of steps they take per day using df - 19 is:

\mathbf{(A)  \ 1596  \ \pm 2.861 \sqrt{ \dfrac{1580^2}{20} + \dfrac{2350^2}{20}}}

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kompoz [17]
A book is sold in Belize for 80.39 Belize dollars.
In Brazil, it sells for 63.65 Brazilian reals.

The exchange rate of US Dollars to Belize Dollars is 1:1.9246
<span>The exchange rate of US Dollars to Brazilian Real is 1:1.7880
</span>
If we convert the two into dollars,
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X = $ 41.77 

</span>Brazilian Real
1 : 1.7880 = X : 63.65 <span> 
</span>1.7880X = 63.65 <span>
X = $ 35.60
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Difference = $ 41.77 - $ 35.60
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<span>So, in Belize the book is more expensive by $ 6.17</span>
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velikii [3]
The answer is:

-2m²+4n²-mn-2m+5n

aka letter c in algebra nation
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2 years ago
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