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musickatia [10]
2 years ago
15

Global Airlines operates two types of jet planes: jumbo and ordinary. On jumbo jets, 25% of the passengers are on business while

on ordinary jets 30% of the passengers are on business. Of Global's air fleet, 40% of its capacity is provided on jumbo jets. (Hint: The 25% and 30% values are conditional probabilities stated as percentages.) What is the probability a randomly chosen business customer flying with Global is on a jumbo jet?
Mathematics
1 answer:
MArishka [77]2 years ago
8 0

Answer:

Answer:

The  probability is  P(J|B) =  0.36

Step-by-step explanation:

B =business

J=jumbo

Or =ordinary

From the question we are told that  

     The proportion of the passenger on business in the ordinary jet  is P(B| Or) =  0.25

     The proportion of the passenger on business in the jumbo jet  is  P(B|J)  =  0.30

     The  proportion of the passenger on jumbo jets is  P(j) = 0.40

      The   proportion of the passenger on ordinary jets is evaluated as

         1 - P(J) =  1- 0.40  =  0.60

According to  Bayer's theorem the probability a randomly chosen business customer flying with Global is on a jumbo jet is mathematically represented as

        P(J|B) =  \frac{P(J) *  P(B|J)}{P(J ) *  P(B|J) +  P(Or ) *  P(B|Or)}

substituting values

         P(J|B) =  \frac{ 0.4 *   0.25}{0.4 *  0.25 +  0.6 * 0.3}

         P(J|B) =  0.36

Step-by-step explanation:

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A math teacher tells her students that eating a healthy breakfast on a test day will help their brain function and perform well
kogti [31]

Answer:

Step-by-step explanation:

Hello!

To test the claim that eating a healthy breakfast improves the performance of students on their test a math teacher randomly asked 46 students what did they have for breakfast before they took the final exam and classified them as:

<u>Group 1</u>: Ate healthy breakfast

X₁: Number of students that ate a healthy breakfast before the exam and earned 80% or higher.

n₁= 26

<u>Group 2: </u>Did not eat healthy breakfast

X₂: Number of students that did not eat a healthy breakfast before the exam and earned 80% or higher.

n₂= 20

After the test she counted the number of students that got 80% or more in the test for each group obtaining the following sample proportions:

p'₁= 0.50

p'₂= 0.40

The parameters of study are the population proportions, if the claim is true then p₁ > p₂

And you can determine the hypotheses as

H₀: p₁ ≤ p₂

H₁: p₁ > p₂

α: 0.05

Z= \frac{(p'_1-p'_2)-(p_1-p_2)}{\sqrt{p'(1-p')[\frac{1}{n_1} +\frac{1}{n_2}] } } }≈N(0;1)

pooled sample proportion: p'= \frac{x_1+x_2}{n_1+n_2} =\frac{13+8}{46} = 0.46

Z_{H_0}= \frac{(0.5-0.4)-0}{\sqrt{0.46(1-0.46)[\frac{1}{26} +\frac{1}{20}] } } }= 0.67

p-value: 0.2514

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value: 0.2514 is greater than the significance level 0.05, the test is not significant.

At a 5% significance level you can conclude that the population proportion of math students that obtained at least 80% in the test and had a healthy breakfast is equal or less than the population proportion of math students that obtained at least 80% in the test and didn't have a healthy breakfast.

So having a healthy breakfast doesn't seem to improve the grades of students.

I hope this helps!

5 0
2 years ago
a perpendicular bisector to is drawn through point c and extended to point d. arrange the pairs of points in order of the y-inte
nirvana33 [79]
Pair 1: slope = (9 - 5)/(8+4) = 1/3
midpoint = ((-4+8)/2, (5+9)/2) = (2, 7)
perpendicular bisector passes through point (2, 7) with slope = -1/(1/3) = -3 giving the equation (y - 7)/(x - 2) = -3 or y - 7 = -3(x - 2) or y = -3x + 13 and y-intercept at y = 13.

Pair 2: slope = (6 - 4)/(-8-2) = -1/5
midpoint = ((2-8)/2, (4+6)/2) = (-3, 5)
perpendicular bisector passes through point (-3, 5) with slope = -1/(-1/5) = 5 giving the equation (y - 5)/(x + 3) = 5 or y - 5 = 5(x + 3) or y = 5x + 20 and y-intercept at y = 20.

Pair 3: slope = (2 - 4)/(7 - 5) = -1
midpoint = ((5+7)/2, (4+2)/2) = (6, 3)
perpendicular bisector passes through point (6, 3) with slope = -1/(-1) = 1 giving the equation (y - 3)/(x - 6) = 1 or y - 3 = (x - 6) or y = x - 3 and y-intercept at y = -3.

Pair 4: slope = (3 - 9)/(-4 - 2) = 1
midpoint = ((2-4)/2, (9+3)/2) = (-1, 6)
perpendicular bisector passes through point (-1, 6) with slope = -1(1) = -1 giving the equation (y - 6)/(x + 1) = -1 or y - 6 = -1(x + 1) or y = -x + 5 and y-intercept at y = 5.

Pair 5: slope = (-12 + 2)/(9 - 3) = -5/3
midpoint = ((3+9)/2, (-2-12)/2) = (6, -7)
perpendicular bisector passes through point (6, -7) with slope = -1(-5/3) = 3/5 giving the equation (y + 7)/(x - 6) = 3/5 or 5(y + 7) = 3(x - 6) or 5y = 3x - 53 and y-intercept at y = -10.6.

Pair 6: slope = (12 - 10)/(8 - 4) = 1/2
midpoint = ((4+8)/2, (10+12)/2) = (6, 11)
perpendicular bisector passes through point (6, 11) with slope = -1(1/2) = -2 giving the equation (y - 11)/(x - 6) = -2 or y - 11 = -2(x - 6) or y = -2x + 23 and y-intercept at y = 23.

Arrangement in order of y-intercepts from smallest to largest
a(3, -2) and b(9, -12)
a(5, 4) and b(7, 2)
a(2, 9) and b(-4, 3)
a(-4, 5) and b(8, 9)
a(2, 4) and b(-8, 6)
a(4, 10) and b(8, 12)

5 0
2 years ago
Read 2 more answers
An animal shelter wants their ratio of dogs to cats to be 3:2. If the animal shelter has 78 dogs, how many cats should they have
OleMash [197]
The simplest way to do this is to set up equivalent fractions. So, you'd do:

\frac{3}{2} = \frac{78}{x} and then solve for x. 

x=52
4 0
2 years ago
Given the polynomial function below,find F(-9). F(x)=-x^2-10x-2
Readme [11.4K]

ANSWER

f( - 9) =  7

EXPLANATION

The given function is

f(x) =  -  {x}^{2}  - 10x - 2

To find f(-9), we substitute x=-9 into the function to obtain:

f( - 9) =  - ( - 9) ^{2}  - 10( - 9) - 2

Simplify:

f( - 9) =  - 81  + 90- 2

Simplify further;

f( - 9) =  7

6 0
2 years ago
A company in Maryland has developed a device that can be attached to car engines, which it believes will increase the miles per
HACTEHA [7]

Answer:

About 0.72

Step-by-step explanation:

Given the data:

With device : 22.6, 23.4, 28.4, 29, 29.3, 20.0

Without device :26.9, 24.4, 20.8, 20.8, 20.2, 26.0, 28.1, 25.6

Using calculator:

With device data:

Sample size (n1) = 6

Degree of freedom (df1) = 6 - 1 = 5

Mean(m1) = 25.45

Variance (s²1) = 15.631

Without device data:

Sample size (n2) = 8

Degree of freedom (df2) = n - 1 = 7

Mean (m2) = 24.1

Variance (s²2) = 9.54

s²t = ((df1/(df1 + df2)) * s²1) + ((df2/(df1 + df2)) * s²2)

s²t = ((5/(5+7)*15.63) + ((7/(5+7))*9.54)

= ((5/12) * 15.63) + ((7/12) * 9.54) = 12.0775

s²m1 = s²t/n1 = 12.0775/6 = 2.0123

s²m2 = s²t/n2 = 12.0775/8 = 1.511

T - statistic :

Tstat = (m1 - m2)/√(s²m1 + s²m2)

Tstat = (25.45 - 24.10) / √(2.0123 + 1.511)

Tstat= 1.350/√3.5233

Tstat = 1.350 / 1.8770455

Tstat = 0.7192153 = 0.72

8 0
2 years ago
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