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Mathematics

2 answers:

mr_godi [17]2 years ago

7 0

Answer:

Step-by-step explanation:

edge2020

Ket [755]2 years ago

4 0

Answer:

14x +10y < 200

Step-by-step explanation:

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A car tire with a radius of 16inches is turning at a rate of 120 revolutions per minute. Find the exact linear speed of the tire

anygoal [31]

Answer:

The speed of the tyre of the car is 1002.24 feet per minute .

Step-by-step explanation:

Given as :

The radius of the car wheel = r = 16 inches

Since 12 inches = 1 feet

So, 16 inches = $\frac{1}{12}$ ×16 = 1.33 feet

The number of revolution of the wheel = 120 revolution per minute

Let The speed of the wheel = s feet per minute

The circumference of wheel = 2 × $\pi$ × radius

where $\pi$ = 3.14

or, circumference = 2 × 3.14 × 1.33

Or, Circumference = 8.352 feet

Now , Speed = circumference of wheel × number of revolution

or, Speed = 8.352 feet × 120 revolution per minute

∴ Speed = 1002.24 feet per minute

Hence The speed of the tyre of the car is 1002.24 feet per minute . Answer

4 0

2 years ago

Which equation has only one solution?

notka56 [123]

Absolute value cannot be less than 0
Solve Absolute Value.|x−5|=−1No solutions.

|−6−2x|=8
x=−7 or x=1

|5x+10|=10
x=0 or x=−4

|−6x+3|=0
 $x = \frac{1}{2}$

So your answer is D) |–6x + 3| = 0

6 0

2 years ago

What is the difference of the polynomials?(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)A–6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5B–6x4y

saul85 [17]

We have to calculate the difference of the given polynomials, we follows as:

$(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-(6x^{4}y-5x^{2}y^{3}-y^{5})$

After opening the brackets, the signs of all the terms changes as there is negative sign before the bracket.

= $(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-6x^{4}y+5x^{2}y^{3}+y^{5})$

Combining all the like terms, we get as

= $(-2x^{3}y^{2})+(4x^{2}y^{3}+5x^{2}y^{3})-3xy^{4}-6x^{4}y+y^{5}$

= $-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^{5}$

Option A is the correct answer.

6 0

2 years ago

Read 2 more answers

The two-way frequency table below shows data on student behavior and the use of positive phone calls home as an incentive for go

dusya [7]

Answer:

From the frequency table, let's calculate the row total.

Row total for phone call = 19 + 9 = 28

Row total for no phone call = 8 +6 = 14

To calculate their respective row relative frequencies, let's use:

Row relative freq = $\frac{freq.}{Row total}$

Now, the two-way frequency table will be computed as:

For phone call:

Desirable behavior = $\frac{19}{28} = 0.67857$ ≈0.69

Undesirable behaviour = $\frac{9}{28} = 0.3214$ ≈0.32

No phone call:

Desirable behaviour = $\frac{8}{14} = 0.5714$ ≈ 0.57

Undesirable behaviour = $\frac{6}{14} = 0.4286$ ≈ 0.43

The complete two-way table is attached.

8 0

2 years ago

Every year the state department of education gathers statistical information from all schools to award a letter grade showing th

DanielleElmas [232]

A school principal used a bar graph to send his report. He assigned the horizontal axis to the student’s name and the vertical axis to the grades. If the x-axis (the horizontal axis) is the students name and the y-axis (the vertical axis) are the grades. There has to be multiple bar-graphs per student. Otherwise the data would be incomplete.

5 0

2 years ago