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Liula [17]
1 year ago
15

After typing 1/4 of a term paper on Friday, Richard completed 2/3 of the remainder on Saturday. If he wanted to finish the paper

that weekend what part was left to be typed on Sunday?
Mathematics
1 answer:
Simora [160]1 year ago
4 0
<u><em>Answer:</em></u>
\frac{7}{12} of the paper

<u><em>Explanation:</em></u>
<u>On Friday:</u>
Richard finished 0.25 of the term paper.
<u>This means that:</u>
Remaining = 1 - 0.25 = 0.75 of the paper

<u>On Saturday:</u>
Richard finished \frac{2}{3} of the remainder.
<u>This means that:</u>
Richard finished \frac{2}{3} *  \frac{1}{4} =  \frac{1}{6}

<u>Now, for Sunday:</u>
We know that Richard finished 0.25 of the paper on Friday and \frac{1}{6} of the paper on Saturday.
<u>This means that:</u>
Total finished = 0.25 + \frac{1}{6} = \frac{5}{12} of the paper
<u>If he wants to finish it by Sunday, then:</u>
He needs to type = 1 - \frac{5}{12} = \frac{7}{12} of the paper

Hope this helps :)
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Answer 1 with Explanation

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Answer 2 with Explanation

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Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

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2 years ago
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