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1 year ago

describe why it might not be good idea to use a,key where each symbols stands for 1 in a picture graph

1 answer:

5 0

Because that is what everyone assumes it to be. So , if it is one, you are just making yourself do more work by making a kind of useless key.

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Snow avalanches can be a real problem for travelers in the western United States and Canada. A very common type of avalanche is

Irina18 [472]

Answer:

We conclude that the mean slab thickness in the Vail region is the same as that in the region of Canada.

Step-by-step explanation:

We are given that slab avalanches studied in a region of Canada had an average thickness of μ = 66 cm.

A random sample of avalanches in spring gave the following thicknesses (in cm);

X: 59, 51, 76, 38, 65, 54, 49, 62, 68, 55, 64, 67, 63, 74, 65, 79.

Let $\mu$ = true mean slab thickness in the Vail region

So, Null Hypothesis, $H_0$ : $\mu$ = 66 cm {means that the mean slab thickness in the Vail region is the same as that in the region of Canada}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 66 cm {means that the mean slab thickness in the Vail region is different from that in the region of Canada}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean thickness = $\frac{\sum X}{n}$ = 61.81 cm

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 10.64

n = sample of avalanches = 16

So, the test statistics = $\frac{61.81-66}{\frac{10.64}{\sqrt{16} } }$ ~ $t_1_5$

= -1.575

The value of t-test statistics is -1.575.

Now, at a 1% level of significance, the t table gives a critical value of -2.947 and 2.947 at 15 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean slab thickness in the Vail region is the same as that in the region of Canada.

7 0

2 years ago

Brett's music teacher spent $134.30 on 17 song books. What is the cost per book?

madreJ [45]

134.3/17 = 7.9
Each book costs $7.9

4 0

1 year ago

The base of a cube is parallel to the horizon. If the cube is cut by a plane to form a cross section, under what circumstance wo

Keith_Richards [23]

This question has this set of answer choices:

a) when the plane cuts three faces of the cube, separating one corner from the others

b) when the plane passes through a pair of vertices that do not share a common face

c) when the plane is perpendicular to the base and intersects two adjacent vertical faces

d) when the plane makes an acute angle to the base and intersects three vertical faces

e) not enough information to answer the question

The right answer is the first choice: a) when the plane cuts three faces of the cube, separating one corner from the others

You can see a picture of this case in the figure attached: as you can see the cross section (in pink) is a triangle.

8 0

1 year ago

Read 2 more answers

A circle with radius of \greenD{1\,\text{cm}}1cmstart color #1fab54, 1, start text, c, m, end text, end color #1fab54 sits insid

MatroZZZ [7]

Answer:

$8.86cm^2$

Step-by-step explanation:

Given the rectangle of 3cm by 4cm and a circle of 1 cm inside it:

The Area of the shaded portion =Area of Rectangle-Area of Circle

Area of a Rectangle=Length X Width $=3 X 4 =12cm^2$

Area of the circle = $\pi r^2=\pi X 1^1=3.142cm^2$

Area of the shaded portion=12-3.142

$=8.86cm^2$

6 0

1 year ago

In a normally distributed data set a mean of 55 where 95% of the data fall between 47.4 and 62.6, what would be the standard dev

tresset_1 [31]

Answer:

The standard deviation of that data set is 3.8

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 55

95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.

Using one of these points.

55 + 2sd = 62.6

2sd = 7.6

sd = 7.6/2

sd = 3.8

The standard deviation of that data set is 3.8

6 0

1 year ago