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VARVARA [1.3K]
2 years ago
6

Joseph’s lunch at a restaurant costs $13.00, without tac. He leaves the waiter a tip of 17% of the cost of the lunch, without ta

x. what is the total cost of the lunch, including the tip, without tax?
A) $2.21
B)$10.78
C)13.17
D)15.21
Mathematics
2 answers:
KonstantinChe [14]2 years ago
3 0
The answer is D

17% of 13 is 2.21

13 + 2.21 = 15.21
Kryger [21]2 years ago
3 0

Answer:

Option D

Step-by-step explanation:

Joseph's lunch costs = $13 without taxes

He leaves tip for the waiter = 17% of cost of the lunch

= 17% of $13

= 13 × \frac{17}{100}

= ( 13 × 0.17)

= $2.21

Total cost of lunch + tip = 13 + 2.21

                                       = $15.21

Option D is the answer.

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1.06 x 10^{10} (3sf)

Step-by-step explanation:

using compound interest formula A = P(1+\frac{R}{100}) ^{n}

from 95 to 08 is 13 yrs

Total Revenue = (5.02 x 10^{9})(1 + \frac{5.9}{100}) ^{13} = 1.057 x 10^{10}

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2 years ago
A basketball player makes 39% of her shots from the free throw line. Suppose that each of her shots can be considered independen
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2 years ago
N ΔCAB, if the measure of segment AB is 8 units and the measure of segment segment AC is 5 units, which of the following could b
muminat

Answer:

∴Third side = 12 units

Step-by-step explanation:

In ΔCAB, the measure of segment AB is 8 units and the measure of segment AC is 5 units.

The sum of two sides of a triangle always grater than third side.

Therefore,

(5+8)=13 units

third side<13

∴Third side = 12 units

4 0
2 years ago
Find the integer a such that<br> a.a ≡ 43 (mod 23) and −22 ≤ a ≤ 0.
Margaret [11]
Given that a is an integer from -22 to 0 such that a is equivalent to 43 (mod 23).

Such a can be obtained as follows:

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8 0
2 years ago
After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ
icang [17]

Answer:

a) Upper Control Limit = 0.10

   Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

            computer manufacturer examined samples of calls to determine

            the frequency of wrong advice given to callers. Each sample

            consisted of 100 calls.

SAMPLE             1   2   3   4   5   6   7   8   9  10 11 12 13 14 15 16

Number of errors 5  3   5   7   4   6   8   4   5    9   3   4   5   6   6   7

To find - a. Determine 95 percent limits.

              b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

  = 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

                                     = 0.0544

⇒P = 0.0544

Now,

Q = 1-P

   = 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = \sqrt{\frac{P.Q}{N} }

                             = 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

        = 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

       = 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0
2 years ago
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