Answer:
95cm
Step-by-step explanation:
45cm is the initial height
each year grow 10cm
growing time 5 years
45+(10 × 5)=95 cm
11/56 inches or 0.196 inches must be removed.
The pipe measures 4/7 inches but needs to be reduced to 3/8 inches.
In order to find out the inches to be removed, you must subtract the length that the pipe should be from the length that it currently is.
<em>Length to be removed = 4/7 - 3/8</em>
You need a common denominator so find the lowest common factor of both denominators:
= 56
In the shared fraction, multiply the numerator by the number you get when you divide 56 by the denominator.
= 56/7 = 8 8 x 4 = 32
= 56 / 8 = 7 7 x 3 = 21
= (32 - 21) / 56
= 11 / 56 inches
= 0.196 inches
In conclusion, 11/56 inches must be removed to get the pipe to 3/8 inches
<em>Find out more at brainly.com/question/4681199.</em>
Answer:
(A)
Step-by-step explanation:
Given the equations:
Substitution simply means replacing the variable y in the second equation with its equivalent x+3 from the first equation.
Substitution of y into 
gives us:
The correct option is A.
Transpose all the terms in the left hand side of the equation. The equation then becomes,
8x² - 22x - 6 =0
Divide both sides of the equation by 2,
4x² - 11x - 3 = 0
In this equation, A = 4, B = -11, and C = -3
With the variables identified, the quadratic equation can be used to identify the roots,
x = (-B +/- √B² - 4AC) / 2A
The values of x in the equation are,
<em> x = 3 and x = -1/4
</em><em />Thus, the one of the answer to this item is the third choice, x = 3. <em>
</em>
Answer:
The correct option is (A) $304.47.
Step-by-step explanation:
The formula to compute the future value (<em>FV</em>) of an amount (A), compounded daily at an interest rate of <em>r</em>%, for a period of <em>n</em> years is:
![FV=A\times [1+\frac{r\%}{365}]^{n\times 365}](https://tex.z-dn.net/?f=FV%3DA%5Ctimes%20%5B1%2B%5Cfrac%7Br%5C%25%7D%7B365%7D%5D%5E%7Bn%5Ctimes%20365%7D)
The information provided is:
A = $300
r% = 1.48%
n = 1 year
Compute the future value as follows:
![=300\times [1+\frac{0.0148}{365}]^{365}\\\\=300\times (1.00004055)^{365}\\\\=300\times 1.014911\\\\=304.4733\\\\\approx \$304.47](https://tex.z-dn.net/?f=%3D300%5Ctimes%20%5B1%2B%5Cfrac%7B0.0148%7D%7B365%7D%5D%5E%7B365%7D%5C%5C%5C%5C%3D300%5Ctimes%20%281.00004055%29%5E%7B365%7D%5C%5C%5C%5C%3D300%5Ctimes%201.014911%5C%5C%5C%5C%3D304.4733%5C%5C%5C%5C%5Capprox%20%5C%24304.47)
Thus, the balance after 1 year is $304.47.
The correct option is (A).
