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Citrus2011 [14]
1 year ago
7

For which discriminant is the graph possible b2-4ac=0 b2-4ac=-1 b2-4ac=4

Mathematics
1 answer:
VARVARA [1.3K]1 year ago
4 0

Answer:

The graph is possible for b^2-4ac=4

Step-by-step explanation:

we know that

The discriminant of a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

D=b^2-4ac

If D=0 the quadratic equation has only one real solution

If D>0 the quadratic equation has two real solutions

If D<0 the quadratic equation has no real solution (complex solutions)

In this problem , looking at the graph, the quadratic equation has two real solutions (the solutions are the x-intercepts)

so

b^2-4ac > 0

therefore

The graph is possible for b^2-4ac=4

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Samantha drew Triangle JKL with the coordinates (2,3), (4, 3) and (5,2). She reflected this image over the x-axis to create an i
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Answer:

J'(2,-3), K'(4, -3) and L'(5,-2)

Step-by-step explanation:

The given triangle has vertices at  J(2,3), K(4, 3) and L(5,2).

The transformation rule for a reflection in the x-axis is:

(x,y)\to (x,-y)

We substitute the points to obtain the coordinates  of the image triangle  J'K'L'

J(2,3)\to J'(2,-3)

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In other words, we negate the y-coordinates of triangle JKL to obtain the coordinates of J'K'L'

See attachment for graph.  

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2 years ago
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Answer:

18 weeks

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Next, solve for x by dividing both sides by 15

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