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Tomtit [17]
2 years ago
9

Water has a density of 1.0 g/cm3. What is the mass of 10.0 cm3 of water?

Mathematics
2 answers:
fgiga [73]2 years ago
8 0
1.0g/cm3 means that the mass of one cm3 is 1.0g
The easiest method to use is the rule of three, and let x be the mass of 10.0 cm3 of water
1g -- > 1.0 cm3
x --> 10.0 cm3

x= (10*1)/1
x=10.0 g

So the mass of 10.0 cm3 of water is 10.0g

Hope this Helps! :)
Bas_tet [7]2 years ago
8 0

Answer:

mass = density × volume

The density of the sample is 1.0 g/cm3, and the volume is 10.0 cm3. Plug in the values and solve:

mass = 1.0 × 10.0 = 10 g

The mass of 10.0 cm3 of water is 10 grams.

I hope I helped you out!  :)))

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Alison is 2/3 of the way to the museum, so the answer is about 2/3 of 9, or 6 miles.  Let's calculate it:

  2                              17 miles
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 3                                    3             miles.
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1 year ago
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If the computer sells for $764 and commission is 6%, then he would make $45.84 off that sale.
 
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2 years ago
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Ava bought some pens for $ 2 each and some pencils for $ 1 each. She bought 3 more pens than pencils and spent a total of $ 12.
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Answer:

Step-by-step explanation:

price of 1 pen= $ 2

price of 1 pencil= $1

total money spent= $12

Let the number of pen be a and number of pencil be b.

 2 a + b = 12   ----------------Equation 1

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5 0
1 year ago
Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
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Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

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x∈ {-1,4} y<0, below x-axis

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2 years ago
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Answer:

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1 year ago
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