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Tomtit [17]
2 years ago
9

Water has a density of 1.0 g/cm3. What is the mass of 10.0 cm3 of water?

Mathematics
2 answers:
fgiga [73]2 years ago
8 0
1.0g/cm3 means that the mass of one cm3 is 1.0g
The easiest method to use is the rule of three, and let x be the mass of 10.0 cm3 of water
1g -- > 1.0 cm3
x --> 10.0 cm3

x= (10*1)/1
x=10.0 g

So the mass of 10.0 cm3 of water is 10.0g

Hope this Helps! :)
Bas_tet [7]2 years ago
8 0

Answer:

mass = density × volume

The density of the sample is 1.0 g/cm3, and the volume is 10.0 cm3. Plug in the values and solve:

mass = 1.0 × 10.0 = 10 g

The mass of 10.0 cm3 of water is 10 grams.

I hope I helped you out!  :)))

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In the xy plane, a quadrilateral has vertices at (-1, 4), (7,4), (7,5), and (-1. 5). What is the perimeter of the quadrilateral?
iris [78.8K]

Answer:

(B) 18.

Step-by-step explanation:

We are asked to find the perimeter of a quadrilateral with vertices at (-1, 4), (7,4), (7,5), and (-1. 5).

First of all, we will draw vertices of quadrilateral on coordinate plane and connect the vertices as shown in the attached photo.

We can see that our quadrilateral is a parallelogram, whose parallel sides are equal.

\text{Perimeter of quadrilateral}=8+1+8+1

\text{Perimeter of quadrilateral}=16+2

\text{Perimeter of quadrilateral}=18

Therefore, the perimeter of the given quadrilateral is 18 units.

8 0
2 years ago
Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the
xenn [34]

Answer:

As per the given statement:

The region bounded by the given curves about the y-axis, y = 13e^{-x^2}, y=0, x = 0 and x = 1

Using cylindrical shell method:

The volume of solid(V) is obtained by rotating about y-axis and the region under the curve y = f(x) from a to b is;

V = \int_{a}^{b} 2\pi x f(x) dx   where 0\leq a

where x is the radius of the cylinder

f(x) is the height of the cylinder.

From the given figure:

radius = x

height(h) =f(x) =y=13e^{-x^2}

a = 0 and b = 1

So, the volume V generated by rotating the given region:

V =2 \pi \int_{0}^{1} x ( 13e^{-x^2}) dx\\\\V=2\pi\left [ -\frac{13}{2}e^{-x^2} \right ]_{0}^{1}\\\\V=2\pi\left (-\frac{13}{2e}-\left(-\frac{13}{2}\right) \right )\\\\V=-\frac{13\pi }{e}+13\pi

therefore, the volume of V generated by rotating the given region is V=-\frac{13\pi }{e}+13\pi










5 0
1 year ago
Part of a book fell out. The first page of this part has number 143. The last page has a number written with the same digits. Ho
Gnom [1K]

Answer:

142 pages

Step-by-step explanation:

The parameters given are

First page of part of the book available = 143

The last is numbered with the digits 143

Since the book is said to have been split into two parts with, we have that one part of the book starts from the beginning, while the other part continue from the first part stops

Number on the pages on the first part = from 1 to number on the first page on the second part - 1

Hence, the part of the book available is the second part and the number of pages in the first part = 1 to 142 or 142 pages.

3 0
1 year ago
The original cost of an item is $64, but you have to pay $78.08. What is the markup of the item (as a percent)?
Neko [114]

Answer:

Step-by-step explanation:

The answer is 22 percent.

5 0
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Recently, 18.3% of visitors to the travelocity web site hailed from the google search engine. a random sample of 130 visitors on
kaheart [24]
In your problem:
p = 18.3% = 0.183
n = 130

The standard error can be calculated by the formula:
SE = √[p · (1 - p) / n]
     = √[0.183 · (1 - 0.183) / 130]
     = 0.0339

The standard error of the proportion is 0.034.
7 0
2 years ago
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