Answer:
- rate of the boat in still water = 6.5 miles / hour
- rate of the current = 2.5 miles / hour.
Explanation:
<u>1) Name the two variables:</u>
- b: rate of the boat in still water:
With that, the net rates of the boat down the river and upstrean are:
<u>2) Now set the equations for the distance as a function of the times and the rates:</u>
- downstream: 18 miles = (b + c) × 2 hours
- upstream: 18 miles = (b - c) × 4.5 hours
<u>3) Set the system of equations:</u>
- 18 = 2(b + c) ⇒ 9 = b + c . . . Equation (1)
- 18 = 4.5 (b - c) ⇒ 4 = b - c . . . Equation (2)
<u>4) Solve the system by </u><u>elimination</u><u>:</u>
- Add equations (1) and (2): 9 + 4 = 2b
- Divide both sides by 2: 13/2 = b
- Replace b with 6.5 in equation (2) and solve:
4 = 6.5 - c ⇒ c = 6.5 - 4 = 2.5
<u>5) Results:</u>
- b = rate of the boat in still water = 6.5 miles / hour
- c = rate of the current = 2.5 miles / hour.
Answer:
No. of gonjas = 52
No. of more nzemas than fantes = 78
Step-by-step explanation:
Total no. of people = 520
No. of fantes =
× 520
No. of fantes = 156
No. of ewes =
× 520 = 130
No. of nzemas =
× 520 = 78
No. of gas =
× 520 = 104
No. of gonjas = 520 - (156 + 130 + 78 + 104) = 52
No. of fantes = 156
No. of nzemas = 78
No. of more nzemas than fantes = 156 - 78 = 78
Pie chart of the following problem is shown below.
1)

.
2)

.
3) The particle is moving right when the velocity function is positive:

or

.
4) When

the particle is slowing down because the acceleration is close to zero

the particle is speeding up when acceleration is increasing away from zero:

.
5)

.
Answer:
tan−1(StartFraction 6.9 Over 9.8 EndFraction)
Step-by-step explanation:
tan−1(StartFraction 6.9 Over 9.8 EndFraction)
tan = opp/adj = 9.8/6.9
tan -1 = 1 / tan = 1 / (9.8 /6.9) = 6.9 /9.8