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2 years ago

6

Given the lines AB and CD, determine the slope of line CD. Type a numerical answer in the space provided. If necessary, use the

/ key to represent a fraction bar.

1 answer:

adell [148]2 years ago

8 0

Answer:

The answer is Slope of CD = -5/4.

Step-by-step explanation:

The question is missing important information like the values for which the slope has to be find

Points A(0,-1), B(5,3), C(2,3), D(6,-2) is missing in the question

Formula for slope:

Slope = $(y_{2}- y_{1})$ / $(x_{2} -x_{1})$

C(2,3), is $(x_{1},y_{1})$

D(6,-2) is $(x_{2},y_{2})$ . for slope of CD.

Putting values in the formula.

Slope = $(-2-3)$ / $(6-2)$

Slope = -5/4

This formula can be used for for finding slope for values of A and B similarly.

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A girl had 20 coins in nickels and dimes whose sum was $1.40. She spent 65cents , using 8 coins. She now has ? nickels.

abruzzese [7]

Answer:

$0.75 nickels

Step-by-step explanation:

$1.40-$0.65=$0.75

$0.75 nickels

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Please help me. The function g(x) is a transformation of f(x). If g(x) has a y-intercept at 3, which of the following functions

Step2247 [10]

<h3>Answer: D. g(x) = f(x)+4</h3>

The graph shows f(x) to have a y intercept at -1, which is where the diagonal line crosses the y axis. We want the y intercept to move to 3. So we must add 4 to the old y intercept to get the new y intercept.

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2 years ago

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A triangle is rotated 90° about the orgin. Which rule describes the transformation

Katen [24]

Step-by-step explanation:

If a triangle is rotated 90° about the origin.

The rule that describes the transformation is

(x, y) → (–y, x)

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2 years ago

Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

FromTheMoon [43]

Answer:

Here is the question attached with.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ is a straight line.

$\angle AEF$ is a right angled triangle.

Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

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