Answer:
The perimeter of Δ ABC is 20 + 2
units ⇒ Last answer
Step-by-step explanation:
The perimeter of any triangle is the sum of the lengths of its three sides
The formula of distance between two points is 
In Δ ABC
∵ A = (3 , 4) , B = (-5 , -2) , C = (5 , -2)
∵ AB = 10 units
∵ AC = 2
- To find its perimeter find the length of BC
∵ 
= -5 and 
= -2
∵ 
= 5 and 
= -2
- By using the formula above
∴ 
∴ 
∴ BC = 10 units
To find the perimeter add the lengths of the three sides
∵ P = AB + BC + AC
∴ P = 10 + 10 + 2
- Add like terms
∴ P = 20 + 2
The perimeter of Δ ABC is 20 + 2 units
Answer:
1/5
Step-by-step explanation:
So the question tells to express the expression in your problem where N0 is N-naught and the symbol represent the lower case Greek letter lambda. So the best answer or expression would be that the lambda is the wavelength of the expression. I hope you are satisfied with my answer
Answer:
A. 4.26 in^2
Step-by-step explanation:
Step 1: Find the area of the sector DBC. Here we have to use the formula.
Area of a sector = Central Angle/360 *π
The area of the sector DBC = (54/360)*3.14*
= 30.16
Step 2: Area of segment CFD = Area of the sector DBC - Area of the ΔCBD
= 30.17 - 25.9
Area of segment CFD = 4.27in^2
