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2 years ago

The box plots show attendance at a school dance competition and school badminton games.

Mathematics

2 answers:

BartSMP [9]2 years ago

5 0

Answer:

The IQR is a better measure of spread for dance competitions than for badminton games.

Step-by-step explanation:

I took the test

Helen [10]2 years ago

4 0

Answer:

The IQR is a better measure of spread for dance competitions than for badminton games.

Step-by-step explanation:

I understand from "Dance Competition box plot has interquartile ranges approximately between 60 and 130" that quartile 1 is at 60 and quartile 3 is at 130, then, the interquartile range (IQR) is 130 - 60 = 70.

Similarly, from Badminton box plot, quartile 1 is at 90 and quartile 3 is at 150, then, the interquartile range is 150 - 90 = 60.

IQR is a measure of statistical dispersion, that is, as IQR increase, spread increase.

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A line passes through the points (p, a) and (p, –a) where p and a are real numbers and p ≠ 0. Describe each of the following. Ex

MissTica

Answer:

Part A) The slope is undefined

Part B) The equation of the line is $x=p$

Part C) None y-intercept

Part D) The slope of a line perpendicular to the given line is equal to zero

Step-by-step explanation:

we have that

Describe

A) slope of the line

B) equation of the line

C) y-intercept

D) slope of a line perpendicular to the given line

Part A) slope of the line

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$(p,a)\ (p,-a)$

Substitute the values

$m=\frac{-a-a}{p-p}$

$m=\frac{-2a}{0}$ -----> the slope is undefined

Its a vertical line (parallel to the y-axis)

Part B) Equation of the line

we know that

The equation of a vertical line is equal to the x-coordinate of the points through which the line passes.

$x=p$

Part C) The y-intercept

The y-intercept is the value of y when the value of x is equal to zero

The vertical line not intercept the y-axis

None y-intercept

Part D) slope of a line perpendicular to the given line

A line perpendicular to the given line is a horizontal line (parallel to the x-axis)

therefore

The slope is equal to zero

6 0

2 years ago

The table below shows the amount paid for different numbers of items. Determine if this relationship forms a direct variation. V

Elden [556K]

<h2>Answer/Step-by-step explanation:</h2>

Direct variation occurs when a variable varies directly with another variable. That is, as the x-variable increases, the y-variable also increases.

The ratio of between y-variable and x-variable would be constant.

Direct variation can be represented by the equation, $y = xk$ , where k is a constant. Thus,

$\frac{y}{x} = k$

From the table given, it seems, as x increases, y also increases. Let's find out if there is a constant of proportionality (k).

Thus, ratio of y to x, $\frac{0.50}{1} = 0.5$

k = 0.5.

If the given table of values has a direct variation relationship, then, plugging in the values of any (x, y), into $\frac{y}{x} = k$ , should give us the same constant if proportionality.

Let's check:

When x = 2, and y = 1:

$\frac{y}{x} = k$ ,

$\frac{1}{2} = 0.5$ ,

When x = 3, y = 1.5:

$\frac{1.5}{3} = 0.5$ ,

When x = 5, y = 2.50:

$\frac{2.5}{5} = 0.5$ ,

The constant of proportionality is the same. Therefore, the relationship forms a direct variation.

5 0

2 years ago

r Flag For Review A certain city with a population of 132,000 is to be divided into 11 voting districts, and no district is to h

Alex787 [66]

Answer:

$P = \frac{132000}{12}=11000$

So then P =11000 is the minimum that the least populated district could have.

Step-by-step explanation:

We have a big total of N = 132000 for the population.

And we know that we divide this population into 11 districts

And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"

Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P

The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:

$P + 10 (1.1P) = 12 P= 132000$