Absolute value cannot be less than 0
Solve Absolute Value.<span><span>|<span>x−5</span>|</span>=<span>−1</span></span>No solutions.
<span>|<span><span>−6</span>−<span>2x</span></span>|</span>=8
<span>x=<span>−<span><span>7<span> or </span></span>x</span></span></span>=<span>1
</span>
<span>|<span><span>5x</span>+10</span>|</span>=10
<span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−4</span>
<span>|<span><span>−<span>6x</span></span>+3</span>|</span>=<span>0
</span>
So your answer is D) |–6x + 3| = 0
Answer:
The fraction of the students who failed to went partying = 
Step-by-step explanation:
Let total number of students = 100
No. of students partied are twice the no. of students who not partied.
⇒ No. of students partied = 2 × the no. of students who are not partied
No. of students partied before the exam = 20 % of total students
⇒ No. of students partied before the exam = 
× 100
⇒ No. of students partied before the exam = 20
No. of students who not partied before the exam = 
Thus the fraction of the students who failed to went partying = 
Answer:
Step-by-step explanation:
Given that Miguel is playing a game
The box contains 4 chips, 2 with number 1, and other two differntly numbered as 3 and 5.
OUt of these 4, 2 chips are drawn
P(drawing same number) = 2C2/4C2 =
Prob (drawing differnt numbers) = 1-1/6 =
Hence prob of winning 2 dollars =
Prob of losing 1 dollar =
b) Expected value = sum of prob x amount won
= 
c) Miguel can expect to lose 1/2 dollars for every game he plays
d) If it is to be a fair game expected value =0
i.e. let the amount assigned be s
Then 
Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:
So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B25%7D%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
The answer is 1 gallon.
Miles per gallon(mpg) is computed by dividing the distance traveled by the how many gallons used. So you can derive a formula for how many gallons you would use given the mpg. You will end up with:
The problem asks for how many gallons of gas she will safe in a five-day work work week. So first you need to compute how many miles that would be.
54 miles/day x 5days =
270 milesSo in a five day work week, she will travel 270 miles.
Now to see how much gas she will save, compute how many gallons she will use up for each car, given the mpg of each and find the difference.
First model:30 mpg
This means that with the first model, she will have used up
9 gallons in a 5-day work week.
Second model: 27 mpg
This means that with the second model, she will have used up 10g in a 5-day work week.
Now for the last bit. How much will she save? You can get that by getting the difference of how many gallons each car would have used up.
10gallons - 9gallons = 1gSo she would have saved
1 gallon of gas if she buys the first car instead of the second.
