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fenix001 [56]
1 year ago
9

Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t

hat the distribution of arrival time can be modeled using an exponential distribution with a mean of 4 minutes (i.e. the mean number of arrivals is 1/4 per minute), find the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot.
Mathematics
1 answer:
Ber [7]1 year ago
3 0

Answer:

The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of time until the next student will arrive in the library parking lot at the university.

The random variable <em>X</em> follows an Exponential distribution with mean, <em>μ</em> = 4 minutes.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda e^{\lambda x};\ x\geq 0, \lambda >0

The parameter of the exponential distribution is:

\lambda=\frac{1}{\mu}=\frac{1}{4}=0.25

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10}{0.25e^{-0.25x}}\, dx

                 =0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821

Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

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Answer:

<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>

Step-by-step explanation:

Given the function  j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6}, to show that both equality functions are true, all we need to show is that both  j(k(x)) and k(j(x)) equal x,

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j[(ln x/11.6)] = x

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Similarly for k[j(x)];

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Equation:

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