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BaLLatris [955]
2 years ago
12

Please help would be very very appreciated

Mathematics
2 answers:
poizon [28]2 years ago
8 0
115 ounces is the answer
grandymaker [24]2 years ago
7 0

Answer:

115

Step-by-step explanation:

I hoped I help friend◇

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Solve 7x- c= k for x. <br>A. X = 7(k+C) <br>B. x = 7(K-C) <br>C. X = k+c/7 <br>D. X= k-c/7​
antoniya [11.8K]

Answer:

C

Step-by-step explanation:

you add c to both side which will then make it 7x=k+c then you would divide 7 from both sides leaving you with x=k+c/7. Except 7 will be under the k and c.

7 0
2 years ago
Robert has $50 to spend on his utility bills each month. The basic monthly charge is 23.77 electricity costs 0.1117 for each kil
Lilit [14]

Answer:

<em>The maximum number of kilowatt-hours is 235</em>

Step-by-step explanation:

<u>Inequalities</u>

Robert's monthly utility budget is represented by the inequality:

0.1116x + 23.77 < 50

Where x is the number of kilowatts of electricity used.

We are required to find the maximum number of kilowatts-hours used without going over the monthly budget. Solve the above inequality:

0.1116x + 23.77 < 50

Subtracting 23.77:

0.1116x < 50 - 23.77

0.1116x < 26.23

Dividing by 0.1116:

x < 26.23/0.1116

x < 235

The maximum number of kilowatt-hours is 235

7 0
1 year ago
Solve the equation using square roots. 6x2 = 54
Mars2501 [29]
6x^2 = 54

6(x^2) = 54

6(x^2)/6 = 54/6

x^2 = 9

rt(x^2) = rt(9)

x = 3

hope this helps
5 0
2 years ago
Read 2 more answers
ANSWER THE QUESTION BELOW FOR 10 POINTS AND BRAINLEST
nlexa [21]

Answer:

C I think

Step-by-step explanation:

7 0
1 year ago
Read 2 more answers
Automobile mechanics conduct diagnostic tests on 150 new cars of a particular make and model to determine the extent to which th
Aleks04 [339]

Answer:

99% Confidence interval: (0.185,0.375)                                                  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 150

Number of cars that have faulty catalytic converters, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{150} = 0.28

99% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.58

Putting the values, we get:

0.28\pm 2.58(\sqrt{\frac{0.28(1-0.28)}{150}}) = 0.28\pm 0.095\\\\=(0.185,0.375)

The​ 99% confidence interval for the true proportion of new cars with faulty catalytic converters is​ (0.185,0.375)

8 0
2 years ago
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