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2 years ago

Please help would be very very appreciated

Mathematics

2 answers:

poizon [28]2 years ago

8 0

115 ounces is the answer

grandymaker [24]2 years ago

7 0

Answer:

115

Step-by-step explanation:

I hoped I help friend◇

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Juan buys 2.8 pounds of turkey. The turkey costs $4.55 for each pound. How much does Juan spend for the turkey?

nadya68 [22]

Answer:12.75

Step-by-step explanation:

2.8X4.55

4 0

2 years ago

Read 2 more answers

Can someone help please

riadik2000 [5.3K]

Answer:

62 Sunday papers were sold

Step-by-step explanation:

Let x represent the number of Sunday papers sold. Then half that many, or x/2, is the number of Friday papers sold. The total revenue from the sales is the sum of products of quantity and price:

1.50 · x + 0.75 · (x/2) = 116.25

Multiplying by 2, this becomes ...

3.00x +0.75x = 232.50

3.75x = 232.50

Dividing by the coefficient of x gives ...

232.50/3.75 = x = 62

The number of Sunday newspapers sold is 62.

6 0

2 years ago

FIRST ONE TO ANSWER GETS BRAINLIEST Henry divided his socks into five equal groups. Let s represent the total number of socks. W

Alex777 [14]

Answer: There are 20 socks in the first case and there are 75 socks in the second case.

Step-by-step explanation:

Since we have given that

Number of equal groups = 5

Let the total number of socks be 's'.

According to question, expression will be

Now, Suppose number of socks in each group = 4

So, it will become,

Suppose number of socks in each group = 15

So, Total number of socks become

Hence, there are 20 socks in the first case and there are 75 socks in the second case.

3 0

2 years ago

An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed, with mean equ

kompoz [17]

Answer:

0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 800, \sigma = 40, n = 16, s = \frac{40}{\sqrt{16}} = 10$

Find the probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

This probability is the pvalue of Z when $X = 775$ . So

$Z = \frac{X - \mu}{s}$

$Z = \frac{775 - 800}{10}$

$Z = -2.5$

$Z = -2.5$ has a pvalue of 0.0062. So there is a 0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

5 0

2 years ago

Drag and drop an answer to each box to correctly complete the explanation for deriving the formula for the volume of a sphere.

Advocard [28]

The volume of a sphere is given by:

$V= \frac{4}{3} \pi r^{3}$

So, we need to deduct this equation. We will walk through Calculus on the concept of a solid of revolution that is a solid figure that is obtained by rotating a plane curve around some straight line (the axis of revolution) that lies on the same plane. We know from calculus that:

 $V=\pi \int_{a}^{b}[f(x)]^{2}dx$

Then, according to the concept of solid of revolution we are going to rotate a circumference shown in the figure, then:

 $x^{2}+y^{2}=r^{2}$

Isolationg y:

 $y= \sqrt{r^{2}-x^{2}}$ 

So,

 $f(x)=y=\sqrt{r^{2}-x^{2}}$ 

 $V=\pi \int_{a}^{b}[\sqrt{r^{2}-x^{2}}]^{2}dx$

 $V=\pi \int_{a}^{b}(r^{2}-x^{2})dx$ 

being -r and r the limits of this integral.

 $V=\pi \int_{-r}^{r}(r^{2}-x^{2})dx$

Solving:

 $V=\pi[r^{2}x-\frac{x^{3}}{3}]\right|_{-r}^{r}$

Finally:

 $V=\pi(r^{3}-\frac{r^{3}}{3})-\pi(-r^{3}+\frac{r^{3}}{3})= \frac{4}{3} \pi r^{3}$

5 0

2 years ago

Read 2 more answers