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1 year ago

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Lydia spent 4/5 of her money on a mobile phone and 2/3 of the remaining amount on a bag. She had $60 left. How much more money d

id she spend on the mobile phone than on the bag?

1 answer:

KengaRu [80]1 year ago

5 0

The answer is 600 because 1 out 3 is 60 so to find the bag multiply by two while to find 1 out 5 of her monet take 60 times 3 which is 180. 180 times 4 is the money she spent on her mobile phone so take the money spent on her mobile phone(720)minus the amount of money spent on the bag(120)

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Four friends are playing a game. They randomly choose a handful of marbles from a bag. The player with the highest ratio of blue

Monica [59]

We are given the number of Blue and Purple Marbles for each of the four friends. So first we have to find the ratio of blue marbles to purple marbles for each of them.

A) Rosa

Number of blue marbles = 10

Number of purple marbles = 12

Ratio of blue to purple marbles = $\frac{10}{12}=0.833$

B) Chi

Number of blue marbles = 5

Number of purple marbles = 6

Ratio of blue to purple marbles = $\frac{5}{6}=0.833$

C) Alberto

Number of blue marbles = 5

Number of purple marbles = 12

Ratio of blue to purple marbles = $\frac{5}{12}=0.417$

D) Pedro

Number of blue marbles = 10

Number of purple marbles = 6

Ratio of blue to purple marbles = $\frac{10}{6}=1.667$

From the above calculations we can see that Pedro has the highest value of ratio for blue marbles to purple marbles. Also we can see Pedro is the only one for whom the number of blue marbles is more than the number of purple marbles. So this confirms that our calculation is correct.

Thus, the player which gets to go first is Pedro.

4 0

1 year ago

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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Volgvan

Answer: We reject the null hypothesis, and we use Normal distribution for the test.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis : $H_0:\mu\geq 50000$

Alternate hypothesis : $H_1:\mu$

There is 5% level of significance.

$\bar{X}=46800\\\\\sigma=9800\\\\n=29$

So, the test statistic would be

$z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{46800-50000}{\dfrac{9800}{\sqrt{29}}}\\\\z=-1.75$

Since alternate hypothesis is left tailed test.

So, p-value = P(z≤-2.31)=0.0401

And the P-value =0.0401 is less than the given level of significance i.e. 5% 0.05.

So, we reject the null hypothesis, and we use Normal distribution for the test.

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2 years ago

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vitfil [10]

To graph it, just graph $y=-3^{-x}-6$ and $y=-3^x+10$ and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
$3^{-x}+6=3^x-10$
multiply both sides by $3^x$
$3^0+6(3^x)=3^{2x}-10(3^x)$
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minus 1 from both sides and minus 6(3^x) from both sides
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use u subsitution
$u=3^x$
we can rewrite it as
$0=u^2-16u-1$
now factor
I mean use quadratic formula
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so for 0=u^2-16u-1, a=1, b=-16, c=-1
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$u=8+/-\sqrt{65}$
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
$u=8+\sqrt{65}=3^x$
$8+\sqrt{65}=3^x$
if you take the log base 3 of both sides you get
$log_3(8+\sqrt{65})=x$
if you use ln then
$ln(8+\sqrt{65})=xln(3)$
then
$\frac{ln(8+\sqrt{65})}{ln(3)}=x$

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1 year ago

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Elis [28]

The answer is 8 marbles. 6*8=48. 48(ednas marbles) + 8(sam's marbles)=56.

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The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t

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2 years ago

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