Answer:
speed = 796142.197 km/hr
Step-by-step explanation:
solution
we consider here orbit around galactic center is circular so
circumference formula will be here
circumference C = 2πr ........1
here we know r = 27000
so
circumference C = 2 π × 27000
C = 169560 light year
so
we travel 169560 light year in 230000000 years
so distance will be
distance = 
distance = 0.00073721 light year/year
and we know 1 year = 8760 hours
so 1 light year = 9.46027 ×
km
so
sped of moving is
speed = 0.00073721 × 9.46027 ×
km/hr
speed = 796142.197 km/hr
Answer:
<u>The number of intersections = ∞</u>
Step-by-step explanation:
Given the system of equations:
0.5 x + 5y = 6
3x + 30y = 36
By multiplying the first equation by 6
∴ 6 (0.5 x + 5y) = 6 * 6
∴ 3x + 30y = 36
So, Those equations are "Dependent", because they are really the same equation, just multiplied the first equation by 6.
So, the two equations are identical
Therefore: <u>They have infinity number of solutions.</u>
<u>See the attached figure.</u>
0.5 x + 5y = 6 ⇒ in black color
3x + 30y = 36 ⇒ in red color
Answer:

So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:


So then P =11000 is the minimum that the least populated district could have.
Answer:
C. 3 : 5
D. 24 : 40
Step-by-step explanation:
Select two ratios equivalent to 6 : 10
Checking all options
A. 20 : 12
20 / 12
= 10 /6
= 10 : 6
B. 32 : 50
= 32 / 50
= 16 / 25
C. 3 : 5
3 / 5
= 6 / 10
3/5 is equivalent to 6 / 10
D. 24 : 40
24 / 40 = 12 / 20
= 6 / 10
= 6 : 10
Options C and D are correct
The rhombus has 2 obtuse angles, and 2 acute angles. the square has 4 right angles.