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crimeas [40]
2 years ago
14

he temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the

equation K = C + 273.15. When solved for C, the equation is
Mathematics
2 answers:
PIT_PIT [208]2 years ago
5 0
We have that
<span>K = C + 273.15
solve for C
subtract 273.15 both sides
K-273.15=C
C=K-273.15

the answer is
</span>C=K-273.15<span>


</span>
emmasim [6.3K]2 years ago
5 0
For this case we have the following equation:
 K = C + 273.15&#10;
 Where,
 C: It is the temperature measured in degrees Celsius
 K: It is the temperature measured in Kelvin
 From here, we must clear the value of C.
 To do this, we subtract 273.15 from both sides of the equation.
 We have then:
 K - 273.15 = C + 273.15 - 273.15&#10;
 Rewriting we have:
 K - 273.15 = C + 0&#10;&#10;C = K - 273.15
 Answer:
 
solved for C, the equation is:
 
C = K - 273.15
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Answer:

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Step-by-step explanation:

3(x - 14) = 3

3x - 42 = 3

3x = 42 + 3 = 45

x = 15.

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Bria and Matt have a total of 400 stamps. Matt has three times as many stamps as Bria. Which system of equations can be used to
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Zucchini plants require 9 square feet around each plant.
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What is the sum of the distinct prime factors of 315
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The graph of f(x) = StartRoot x EndRoot is reflected across the x-axis and then across the y-axis to create the graph of functio
Anna35 [415]

Answer:

<em>The only value that is in the domains of both functions is 0</em>

<em>The range of g(x) is all values less than or equal to 0</em>

Step-by-step explanation:

As the original function is

f(x) = \sqrt{x}

Since, domain is the set of all possible input values that define the function, and range is the set of all possible output values for all possible domain values for which the function is defined.

  • The domain of f(x) = \sqrt{x} will be [0, ∞)
  • The range of f(x) = \sqrt{x} will be [0, ∞)

Please check the attached <em>figure a</em> for visualizing the graph of f(x) = \sqrt{x}.

<u><em>Impact of double transformation:</em></u>

  • When the function f(x) = \sqrt{x} is reflected across x-axis, the function becomes y = -\sqrt{x} after first transformation
  • After the second transformation across y-axis, the function y = -\sqrt{x} becomes  g(x) = -\sqrt{-x}

For

g(x) = -\sqrt{-x}

-x must be equal to or greater than zero for g(x) = -\sqrt{-x} to be defined i.e. -x ≥ 0.

So,

-x ≥ 0 can be written as x≤ 0

So,

  • The domain of g(x) = -\sqrt{-x} will be (∞, 0]
  • The range of g(x) = -\sqrt{-x} will be (∞, 0]

Please check the attached figure a for visualizing the graph of g(x) = -\sqrt{-x}.

So, from the above discussion, we can say that

  • 0 is the only that is in the domain of both function.
  • The range of g(x) is all values less than or equal to 0

So,

Only two statements are true about the functions f(x) and g(x) are true which are:

<em>The only value that is in the domains of both functions is 0</em>

<em>The range of g(x) is all values less than or equal to 0</em>

<em>Keywords: graph, function</em>

<em>Learn more about graph and function from brainly.com/question/11152594</em>

<em>#learnwithBrainly</em>

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