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liberstina [14]
1 year ago
15

Which are linear pairs? Check all that apply.

Mathematics
2 answers:
aleksley [76]1 year ago
7 0

Answer:

B, C, and D

Step-by-step explanation:

boyakko [2]1 year ago
5 0

Answer:

Options B, C and D

Step-by-step explanation:

Linear pair of angles means sum of the angles of the pair is 180° which are formed at a point of a line.

In other words, pair of supplementary angles is the linear pair.

From the figure attached,

Pair of the linear angles are,

1). ∠BAC and ∠CAD

2). ∠BAE and ∠EAD

3). ∠EAD and ∠DAC

Therefore, Options B, C and D are correct.

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When a certain basketball player takes his first shot in a game he succeeds with probability 1/2. If he misses his first shot, h
Gnom [1K]

Answer:

we are given

basketball player Chauncey Billups of the Detroit Pistons makes free throw shots 88% of the time

so, probability of making shot is

=88%

so, p=0.88

To find the probability of missing first shot and making the second shot

so, we can use formula

probability = p(1-p)

now, we can plug values

we get

So, the probability that he misses his first shot and makes the second is 0.1056........Answer

Step-by-step explanation:

3 0
1 year ago
Mr. Velasquez built a playground. It has one section with a slide and another section with a swing set. A pathway connects the t
posledela

Answer:

A_1 = 24m^2 -- Swing set

A_2 = 16m^2 -- Slide

A_3 = 5m^2 --- Pathway

Step-by-step explanation:

Missing part of the question:

Fill in the table above to show the area of each section (see attachment for table)

The area of each section is calculated as:

Area = Length * Width

For the Swing set

A_1 = 8m * 3m

A_1 = 24m^2

For the Slide

A_2 = 8m * 2m

A_2 = 16m^2

For the Pathway

A_3 = 5m * 1m

A_3 = 5m^2

The total area is:

Area=A_1 + A_2 + A_3

Area = 24m^2 + 16m^2 + 5m^2

Area = 45m^2

4 0
1 year ago
Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random
lesya692 [45]
Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes P_B(A).

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
P(A|B)= \frac{P(A \cap B)}{P(B)}

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is \frac{1}{3}

Part A:
To find <span>the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}

</span><span>P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

</span><span>Thus P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}

Therefore, P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}


Part B:
</span>To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime<span>, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.
</span><span>
P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}

</span><span>P(D)= \frac{1}{3}</span><span>

Therefore, P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}</span>
3 0
2 years ago
the richmond park gamekeeper wanted to know how many deer were in the park . he caught 90 of them and put a small tag round a ho
Alenkasestr [34]

Answer:

a. Since 10 out of 70 had a tag we can write the ratio 10:70. We need to solve for x in 90:x. x = 630 so the answer is 630.

b. An assumption he could have made is that the number of deer that had a tag and the total amount of deer were directly proportional.

5 0
1 year ago
Find the percentage change between two numbers if the original number was 150 and now is 330.
bearhunter [10]

Answer:

0.45

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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