M = Tim's dollar amount
R = Rebecca's dollar amount
MR = Tim and Rebecca's dollars together
R = (M x 1/10) - 6
MR = M + ((M x 1/10) - 6)
MR = 70 + ((70 x 1/10) - 6)
MR = 70 + (7 - 6)
MR = 70 + 1
MR = 71
Answer: First option is correct.
Step-by-step explanation:
Enrollment month Actual Predicted Residual
January 500 8 4
February 400 15 -1
March 550 15 -1
April 13 12 -1
May 16 17 -1
June 14 15 -1
Since we know that
Residual value = Actual value - Predicted value
Sum of residuals is given by
since we can see that sum of residual is more than 0.
So, it can't be a good fit .
Hence, No, the equation is not a good fit because the sum of the residuals is a large number.
Therefore, First option is correct.
NOTE THIS IS AN EXAMPLE:
Let t = time, s = ostrich, and g = giraffe.
Here's what we know:
s = g + 5 (an ostrich is 5 mph faster than a giraffe)
st = 7 (in a certain amount of time, an ostrich runs 7 miles)
gt = 6 (in the same time, a giraffe runs 6 miles)
We have a value for s, so plug it into the first equation:
(g + 5)t = 7
gt = 6
Isolate g so that we can plug that variable value into the equation:
g = 6/t
so that gives us:
(6/t + 5)t = 7
Distribute:
6 + 5t = 7
Subtract 6:
5t = 1
Divide by 5:
t = 1/5 of an hour (or 12 minutes)
Now that we have a value for time, we can plug them into our equations:
1/5 g = 6
multiply by 5:
g = 30 mph
s = 30 + 5
s = 35 mph
Check by imputing into the second equation:
st = 7
35 * 1/5 = 7
7 = 7
The terms in a geometric sequence are given by: A = ar^(n-1)
where A is the nth term in the sequence.
a = first term in the sequence (-2)
r = common ratio (-5)
n = number of the term (4)
A = (-2)(-5)^(4-1)
A = (-2)(-5)^(3)
A = (-2)(-125)
A = 250
I think the best option here is B. <span>period 2pi/3 and asymptote at x=0
</span>because period of tanx is pi so period of tan(3/2x) is pi/(3/2) = 2pi/3. I hope this can work good for you.
