You can make about 11 burgers with that
Answer:
4.43
Step-by-step explanation:
7.90
- 3.47
__________
4. 4 3
I couldn't regroup but of you cross out 0 and put 10, 10-7= 3
and you have to borrow one from 9 and make it 8 and 8-4=4
Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,
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I believe the correct given equation is in the form of:
4 – 0.25 g + 0.5 h
Now we are to evaluate the equation with the given values:
g = 10 and h = 5
What this actually means is that to evaluate simply means
to calculate for the value of the equation by plugging in the values of the
variables. Therefore:
4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)
4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5
4 – 0.25 g + 0.5 h = 4
Therefore the value of the equation is:
4
Answer: at 11:54
Step-by-step explanation:
Let's define the 10:30 as our t = 0 min.
We know that Train A stops every 12 mins, and Train B stops every 14 mins, they will stop at the same time in the least common multiple of 12 and 14.
To find the least common multiple of two numbers, we must do:
LCM(a,b) = a*b/GCD(a,b)
Where GCD(a, b) is the greatest common divisor of a and b.
In this case the only common divisior of 12 and 14 is 2.
So we have:
LCM(12, 14) = 12*14/2 = 84.
Then the both trains will stop 84 minutes after 10:30
one hour has 60 mins, so we can write 84 minutes as:
1 hour and 24 minutes = 1:24
Then they will stop at the same time at 10:30 + 1:24 = 11:54
