Answer:
21.07 yd^2
Step-by-step explanation:
The width of the rectangle is also the radius of the semicircle. The length of the rectangle is 2 radii, or 14 yd.
The area of the shaded region is the same as the area of the semicircle subtracted from the area of the rectangle.
area of shaded region = area of rectangle - area of semicircle
A = LW - (1/2)(pi)r^2
A = 14 yd * 7 yd - (1/2)(3.14)(7 yd)^2
A = 98 yd^2 - (1.57)(49 yd^2)
A = 98 yd^2 - 76.93 yd^2
A = 21.07 yd^2
Answer:
D) 3
Step-by-step explanation
The stem of 3 would have 3 leaves of (0, 1, and 4) from the numbers -> (34, 30, and 31)
2n,perimeter of rectangle is 12n ( width is 2n because length is twice of the width)
1/2 of that ( because the perimeter of the rectangle is twice of the equilateral triangle) is 6n. Since its an equilateral triangle, divide 6n by 3 to get 2n
Answer:
its A.
Step-by-step explanation:
i just took the test