Ask question

Ask question

All categories

2 years ago

14

The range for the Kentucky temperatures is . The range for the Illinois temperatures is . The IQR for the Kentucky temperatures

is . The IQR for the Illinois temperatures is . The box plots show

1 answer:

natima [27]2 years ago

3 0

The boxplot required to answer the questions is attached below :

Answer:

The range for the Kentucky temperature :

(58.3 - 52.2) = 6.1

The range for the Illinois temperature :

(55 - 49.9) = 5.1

The IQR for the Kentucky temperature :

(57.3 - 54.5) = 2.8

The IQR for the Illinois temperature :

(53.3 - 50.9) = 2.4

Step-by-step explanation:

Range = maximum - minimum

Maximum and minimum values are given by the values at the end and start of the whisker.

The range for the Kentucky temperature :

(58.3 - 52.2) = 6.1

The range for the Illinois temperature :

(55 - 49.9) = 5.1

IQR = Q3 - Q1

Q3 = Value at the end of the box

Q1 = value of start of box

The IQR for the Kentucky temperature :

(57.3 - 54.5) = 2.8

The IQR for the Illinois temperature :

(53.3 - 50.9) = 2.4

You might be interested in

A rectangular prism must have a base with an area of no more than 27 square meters. The width of the base must be 9 meters less

den301095 [7]

Answer:

The maximum height of the prism is $12\ m$

Step-by-step explanation:

Let

x------> the height of the prism

we know that

the area of the rectangular base of the prism is equal to

$A=L*W$

$A\leq 27\ m^{2}$

so

$L*W\leq 27$ -------> inequality A

$W=x-9$ ------> equation B

$L=W+6$ -----> equation C

Substitute equation B in equation C

$L=(x-9)+6$

$L=x-3$ ------> equation D

Substitute equation B and equation D in the inequality A

$(x-3)*(x-9)\leq 27$ -------> using a graphing tool to solve the inequality

The solution for x is the interval----------> $[0,12]$

see the attached figure

but remember that

The width of the base must be $9$ meters less than the height of the prism

so

the solution for x is the interval ------> $(9,12]$

The maximum height of the prism is $12\ m$

8 1

2 years ago

Read 2 more answers

Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance o

g100num [7]

Answer:

The value is $k =109.6 \ miles$

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

The distance from city A to B is AB = 467.3 miles

The bearing from B to C is $\theta_{BC} = N 28.7E$

The bearing from B to A is $\theta_{BA} = N 60.7E$

The bearing from A to B is $\theta_{AB} = S60.7W$

The bearing from A to C is $\theta_{AC} = S79.1W$

Generally from the diagram

$\theta_A = 180 - 60.7 -79.1$

=> $\theta_A = 40.2 ^o$

Also

$\theta_B = 32^o$

and

$\theta_C = 180 - (\theta_A +\theta_B )$

=> $\theta_C = 180 - (40.2 + 32 )$

=> $\theta_C = 107.8 ^o$

Generally according to Sine Rule

$\frac{BC}{sin (\theta_A)} = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}$

=> $\frac{BC}{sin (40.2)} = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}$

So

$\frac{BC}{sin (40.2)} = \frac{467.3 }{sin (107.8)}$

=> $BC = 316.8 \ miles$

Also

$\frac{CA}{sin (32)} = \frac{467.3 }{sin (107.8)}$

$CA = 260 .1 \ miles$

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as

$k = [CA +BC] - AB$

=> $k = [260 .1 +316.8]- 467.3$

=> $k =109.6 \ miles$

4 0

2 years ago

A taxi charges a flat rate of $3.00, plus an additional $0.50 per mile. Carl will only take the taxi home if the cost is under $

Ahat [919]

Answer: Take the bus to save money

Step-by-step explanation:

you plug x for 15, the inequality would be ($0.50 * 15) + $3 < $10. We need a less than sign (<) because Carl says the price has to be under and not equal to.

$7.5 + $3 < $10. After you do simple math and add, you will know that Carl is short of money by 50 cents.

Hope this helps :)

6 0

2 years ago

Read 2 more answers

Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o

alekssr [168]

Draw a diagram to illustrate the problem as shown below.

The area of triangle acb is
A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

4 0

2 years ago

Penny and her two friends each ate 1/6 of cake . how much cake did they eat

Hoochie [10]

They ate 1/3 of the cake

4 0

2 years ago

Read 2 more answers