Ask question

Ask question

All categories

2 years ago

14

An airplane 28,000 feet above ground begins descending at a constant rate of 2,000 feet per minute. Which equation gives the hei

ght, h, of the airplane after m minutes? A) h = 2,000m + 28,000 B) h = 28,000m + 2,000 C) h = 2,000 − 28,000m D) h = 28,000 − 2,000m
30 points

2 answers:

Vinil7 [7]2 years ago

8 0

Answer:

Option D is correct.

An equation: h = 28000 -2000m

Step-by-step explanation:

Let h represents the height of the airplane and m represents the minutes.

As per the given statement: An airplane 28,000 feet above ground begins descending at a constant rate of 2,000 feet per minute.

At ground m = 0

h(0) = 28000 feet.

⇒ An airplane descending at a constant rate (r) = - 2000 feet per minute

then,

height(h) of the airplane after m minutes is given by:

h(m) = 28000 - rm ; where r is the rate descending at constant rate and m is the minutes.

Substitute the given values we get;

h(m)= 28000 -2000m

Therefore, an equation which gives the height, h of the airplane after m minutes is; h = 28000 -2000m

larisa86 [58]2 years ago

5 0

Answer:

It IS D) h = 28,000 − 2,000m!

Step-by-step explanation:

You might be interested in

The product of two rational numbers is -28/75. If one of the numbers is 14/25, find the other

Law Incorporation [45]

Answer:

-3/2

Step-by-step explanation:

Let x be the missing number

x* $\frac{14}{25}$ = $\frac{-28}{75}$
x = $\frac{-28}{75}$ * $\frac{25}{14}$ inverse 14/25 since it's a fraction
x = $\frac{-28*25}{75*14}$
x = $\frac{-4*7*25}{25*3*7*2}$ write 75 as 25*3 and -28 as -4*7 to simplify
x = $\frac{-4}{6}$ -4 is left on the top and 6 = 3*2
x = $\frac{-3*2}{2*2}$
x= $\frac{-3}{2}$

8 0

2 years ago

The ballpark made a total of $15,000 from ticket sales at Wednesday's game. The ballpark charges $20 for each adult ticket and $

IRISSAK [1]

<h3>Answer:</h3>

equations

20a +10c = 15000
c = 3a

solution

300 adult
900 children's

<h3>Step-by-step explanation:</h3>

Let "a" and "c" represent the numbers of adult and children's tickets sold, respectively. The problem statement tells us two relationships between these values:

... 20a +10c = 15000 . . . . . . total revenue from ticket sales

... c = 3a . . . . . . . . . . . . . . . . relationship between numbers of tickets sold

Using the expression for c, we can substitute into the first equation to get ...

... 20a +10(3a) = 15000

... 50a = 15000

... a = 15000/50 = 300 . . . . . adult tickets sold

... c = 3·300 = 900 . . . . . children's tickets sold

8 0

2 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

6 0

2 years ago

According to a report in USAToday, more and more parents are helping their young adult children get homes. Suppose eight persons

Inga [223]

Answer:

a) 95% confidence interval for the population proportion of all young adults in Kentucky who received help from their parents.

( 0.0761 , 0.3239)

b) Margin of error = 0.1264.

Step-by-step explanation:

<u>Explanation</u>:-

Given '8' persons in a random sample of 40 young adults who recently purchased a home in Kentucky received help from their parents.

sample proportion of success $'p' = \frac{8}{40} = 0.2$

q = 1=p

q = 1-0.2 = 0.8

a)

95% confidence interval for the population proportion of all young adults in Kentucky who received help from their parents.

$(p-1.96\sqrt{\frac{pq}{n} } , p+1.96\sqrt{\frac{pq}{n} } )$

$(0.2-1.96\sqrt{\frac{0.2X0.8}{40} } , 0.2+1.96\sqrt{\frac{0.2X0.8}{40} } )$

(0.2 - 0.1239,0.2+0.1239)

( 0.0761 , 0.3239)

b) the margin of error for a 95% confidence interval for the population proportion.

For the 95% confidence interval ∝= 0.05 and zₐ = 1.96≅2.

$Margin of error = \frac{2\sqrt{pq} }{\sqrt{n} }$

$Margin of error = \frac{2\sqrt{0.2X0.8} }{\sqrt{40} }$

Margin of error for a 95% confidence interval for the population proportion.

Margin of error = 0.1264.

4 0

2 years ago

Four brothers each bought two hotdogs and a bag of chips at the concession stand.if the bag of chips was $1.25,and the total was

ahrayia [7]

Answer:

$1.65

Step-by-step explanation:

The total purchase can be described by ...

4(2h +1.25) = 18.20 . . . . where h is the price of a hot dog

8h = 13.20 . . . . . . . . . . . subtract 5.00

h = 1.65 . . . . . divide by 8

The price of a hot dog was $1.65.

5 0

2 years ago