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Snezhnost [94]
2 years ago
13

When x is 2, y is 4, p is 0.5, and m is 2. If x varies directly with the product of p and m and inversely with y, which equation

models the situation?
Mathematics
2 answers:
Nesterboy [21]2 years ago
8 0

Answer:

x=8((m*p)/y)

Step-by-step explanation:

You have that x varies directly with p*m (which means that if the result of m*p increase, x increase)

And you have too that x is inversely with y (which means that if y increase, x decrease).

Then you must get:

x=constant value((m*p)/y)

If the problem says that x is 2, y is 4, p is 0.5, and m is 2

the constant value should be 8, in this way:

x=8((m*p)/y)

If you replace:

x=8((2*0,5)/4)

The result is x=2

galben [10]2 years ago
3 0
Can you elaborate please? What does p and m mean?
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Let us say weight of Javier is x pounds.

Weight of his bother = 80 pounds

Javier is 175 % or 1.75 times heavier than his brother.

So Javier's weight = x pounds= 1.75 *80 = 140 pounds.

Answer: Javier's weight is 140 pounds.

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2 years ago
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2 years ago
Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
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Walter is making a 300-mile trip from Wichita Falls, Texas to Austin, Texas. After the first 120 miles, he continues driving at
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Answer:

about 135 more miles to go

Step-by-step explanation:

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Given:

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0\leq t

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Step-by-step explanation:

Paco wants to keep is monthly bill below $30.

We see that he has to pay a foxed monthly service fee of $15. This means he is only left with a limit of $30 - $15 = $15 for his monthly calls and texts.

That is, the amount he has to pay for texting and calling has to be less than $15.

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That is, Paco has to send and receive less than 75 texts.

So,

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

3 0
2 years ago
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