Ask question

Ask question

All categories

2 years ago

14

Ashton walked into the restaurant and four employees were working registers usually trendline equation to predict how long he wi

ll wait to place his order?

1 answer:

MrRa [10]2 years ago

8 0

Answer:

idk

Step-by-step explanation:

You might be interested in

A store sells both cold and hot beverages. Cold beverages, c, cost $1.50, while hot beverages, h, cost $2.00. On Saturday, drink

Marina86 [1]

2h + 4h (1.5c) = 360 so option b is correct.

3 0

2 years ago

Read 2 more answers

In circle p, st = 30 ft. what is the circumference of the circle? 45p ft 15p ft 10p ft 30p ft

skelet666 [1.2K]

The answer to this question is:

<span>In circle p, st = 30 ft. what is the circumference of the circle?
</span><span>"30p ft"

Hope this helped, Taylenlane7544
Your Welcome :)</span>

5 0

2 years ago

Which graph represents a line with a slope of and a y-intercept equal to that of the line y = x – 2? A coordinate plane with a l

Vera_Pavlovna [14]

Answer:

(A)A coordinate plane with a line starting at (negative 2, negative 4), passing through (0, negative 2) and (2, 1).

Step-by-step explanation:

Given the line: y=x-2

Comparing with the slope-intercept form y=mx+b

Slope, m=1
y-intercept is -2.

Therefore, the point (0,-2) must be on the line.

Only Options A and D have this point.

We then determine which has a slope, m=1.

<u>Option A</u>

Using points (-2,-4) and (0,-2)

Slope, $m=\dfrac{-2-(-4)}{0-(-2)} =\dfrac{-2+4}{2}=1$

<u>Option D</u>

Using points (-3,0) and (0,-2)

Slope, $m=\dfrac{-2-0}{0-(-3)} =-\dfrac{2}{3}$

Therefore, Option A satisfy the requirements.

5 0

2 years ago

Read 2 more answers

Seventy of Myra’s classmates are traveling by bus to a football game in another town. They hired 2 buses, but there were only 64

seraphim [82]

Answer:

C. the number of students who rode on each bus.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

This description assumes the elliptic object is centered at (0, 0). However, since the elliptic object is not fixed, initially i

yKpoI14uk [10]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The derived $h = \frac{b^{2} - 2a^{2} }{2a^{2}}$

Step-by-step explanation:

Step One : Consider the ellipse in equilibrium.

Looking at the ellipse in equilibrium i.e when the ellipse has settled down on the concave support (represented by a parabola ) as shown on the third uploaded image.

Step Two : Consider the ellipse equation.

Generally the equation of the ellipse is given as

$\frac{x^{2}}{a^{2}} + \frac{(y-h)^{2}}{b^{2}}\\$

Also the base on which it rest at equilibrium i.e the parabola is represented by $y = x^{2} -1$

Substituting the value of y in the ellipse equation we have

$\frac{x^{2}}{a^{2}}+ \frac{(x^{2}-1-h)^{2}}{b^{2}}=1$

Let $x^{2} = t$

So the equation becomes

$\frac{t}{a^{2}} + \frac{(t -1 -h)^{2}}{b^{2}} =1$

Rearranging, we get :

$a^{2} t^{2} + (b^{2}- 2a^{2}(h +1))t + a^{2}((h +1 )^{2} -b^{2} =0$

This equation above is a quadratic equation or a bi-quadratic equation in x as t = $x^{2}$

Step Three : Relate the equation an the graph on the third uploaded image

We can see that from the graph , if A and B are the two values of x for which the points is made , then A + B = 0 (because they are symmetric in nature)

From Vieta's Roots(Vieta's formula is a formula that shows the relationship between the coefficients of a polynomial and the sum of its roots )

$ax^{2} + bx + c =0$

with A and B as roots

A+B = $\frac{-b}{a}$

But A + B = 0

So $\frac{-b}{a}$ = 0

or we can say that

$\frac{b^{2} - 2a^{2}(h +1 )}{a^{2}}$

Rearranging we get

$h = \frac{b^{2}- 2a^{2}}{2a^{2}}$

5 0

2 years ago