In order to find the sum of the given rational expressions above, here are the steps.
Firstly, you need to find the LCM of the least common denominator.
So it would look like this:
<span>3x-1 + 3x (3x-1)(x-1) + (2x)(3x)
------ ------- = ---------------------------
2x x-1 2x(x-1)
3x^2-4x+1+6x^2
----------------------
2x(x-1)
And the final result would be this:
9x^2-4x+1
--------------
2x(x-1)
</span>9x^2-4x+1
--------------
2x^2-2x
<span>
Hope that this is the answer that you are looking for.
</span>
Answer:
The answer should be $7,087.50
Step-by-step explanation:
4.50 x 50 = 225
225 x 1.05 = 236.25
236.25 x 30 = 7087.50
The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is
for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin
in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0
the mean is x1 = (</span>79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
<span>its range is R 1= 81.0 -78.4 = 2.6
we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14 , R2=2.3
</span>S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4
<span>
therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0
we can say that the process is not in control.
</span>
Answer:
4
Step-by-step explanation:
We know the other side of the rectangle is 18.
So 18=10+2x
subtract 10
8=2x
divide by 2
x=4
Answer:
(11.76, 12.84)
Step-by-step explanation:
Given that we can assume that the distribution of individual student enrollment units at this college is approximately normal.
Sample mean =12.3
sample std dev s = 1.9 units
Sample size = 47
Std error = 
Z critical value for 95% = 1.96
Margin of error = 
Confidence interval =
=(11.76, 12.84)
