Question

Which statement about 6x2 + 7x – 10 is true? One of the factors is (x + 2). One of the factors is (3x – 2). One of the factors is (2x + 5). One of the factors is (x – 5).

Answer 1

we have that

$6x^{2} +7x-10$

Find the factors

$6x^{2} +7x-10 \\ 6 x^{2} +12x-5x-10=0 \\ 6x(x+2)-5(x+2)=0 \\ (6x+5)*(x+2)=0$

therefore

the factors are
$(6x-5) and (x+2)$

the answer is

One of the factors is $(x+2)$

Answer 2

$6x^2+7x-10=\\ 6x^2+12x-5x-10= \\ 6x(x+2)-5(x+2)= \\ (6x-5)(x+2)$

The true statement is: one of the factors is (x+2).