Which must be true if t + u/ t = 12/11 ?

In March 2015, the Public Policy Institute of California (PPIC) surveyed 7525 likely voters living in California. In the survey,

balandron [24]

Answer:

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

And for this case the confidence interval is given by: (0.275, 0.305)

We can estimate the proportion difference as:

$\hat p_D = \frac{0.275+0.305}{2}=0.29$

And the margin of error would be:

$ME=0.305-0.29=0.015$

So then for this case the possibl two options are:

We are 95% confident that the true difference in proportion of Latinos who view global warming as a serious problem and whites who view global warming as a serious problem is 27.5% to 30.5%.

We are 95% confident that the difference between Latino and white opinions about the severity of global warming is 29% with a margin of error of 1.5%.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion of Latinos who view global warming as a serious problem

$\hat p_A=0.75$ represent the estimated proportion Latinos who view global warming as a serious problem

$n_A$ is the sample size required of Latinos who view global warming as a serious problem

$p_B$ represent the real population proportion of white who view global warming as a serious problem

$\hat p_B =0.46$ represent the estimated proportion of whitewho view global warming as a serious problem

$n_B$ is the sample size required of white

$z$ represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

And for this case the confidence interval is given by: (0.275, 0.305)

We can estimate the proportion difference as:

$\hat p_D = \frac{0.275+0.305}{2}=0.29$

And the margin of error would be:

$ME=0.305-0.29=0.015$

So then for this case the possibl two options are:

We are 95% confident that the true difference in proportion of Latinos who view global warming as a serious problem and whites who view global warming as a serious problem is 27.5% to 30.5%.

We are 95% confident that the difference between Latino and white opinions about the severity of global warming is 29% with a margin of error of 1.5%.

4 0

2 years ago

Ken’s predicted temperature for April is 7ºC. His prediction for May is 2ºC higher than April. He used the number line to solve

tia_tia [17]

Answer: Ken Should have moved 9 units to the right because his prediction for May is 9°C. Moving to the left part of the number line would take Ken into negative degrees. 9°C is warmer than 7°C. Therefore, Ken should have moved 9 units to the right of the number line instead of 2 units to the left.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

For the sequence an = 2n + 1, identify the values of a0 = _____, a1 = _____, a2 = _____, and a3 = _____.

Tresset [83]

Answer:

Option A - $a_0= 2,a_1= 3,a_2= 5,a_3= 9$