Ask question

Ask question

All categories

2 years ago

10

Kurt, Sophia, and Franco had a paper airplane throwing contest after school. Kurt's airplane flew 8.6 yards. Sophia's airplane f

lew 2.2 yards farther than Kurt's airplane. Franco threw his airplane 1.5 times as far as Sophia's airplane. How far did Franco's paper airplane fly?

2 answers:

Mila [183]2 years ago

8 0

Answer: 16.2

Step-by-step explanation:

8.6 + 2.2 = 10.8

10.8 x 1.2 = 16.2

horsena [70]2 years ago

5 0

Answer:

16.2

Step-by-step explanation:

You might be interested in

The evening host of a dinner dance reached into a bowl, mixed all the tickets around, and selected the ticket to award the grand

Scilla [17]

Answer:

Simple random sampling method is used here.

Step-by-step explanation:

Given is that the evening host of a dinner dance reached into a bowl, mixed all the tickets around, and selected the ticket to award the grand door prize.

We can see that this is a simple random sampling method as every name on the ticket has an equal opportunity to get selected.

8 0

2 years ago

Mike and Jasmine have a combined age of 30. Mike is 3 years younger than twice Jasmines age. How old is Mike?

Kamila [148]

Mike is 19.

If you turn the question into an equation it turns to:
J x 2 - 3 = M

So since you don’t know Jasmine’s age you would use guess and check. 8,9, and 10 didn’t work but when you put in 11:
11 x 2 - 3 = M
22 - 3 = M
19 = M

And to check your work
J + M has to equal 30 so,
11 + 19 = 30
30 = 30

6 0

2 years ago

Last year Boris paid £256 for his car insurance.

jenyasd209 [6]

Answer:

The percentage increase in the cost of Boris car insurance cost is 249%

Step-by-step explanation:

In this question, we want to calculate the percentage increase in the cost of car insurance paid by Boris

Mathematically, to calculate this percentage increase, we shall need to make use of a mathematical formula.

Mathematically, the percentage increase would be;

{(new value paid-old value paid)/old value paid} * 100%

From the question, we can identify that the old value paid is £256 while the new value paid is £894

Thus, the percentage increase would be ;

(894-256)/256 * 100% = 638/256 * 100 = 2.4921875 * 100 = 249.21875 which is 249% increase to the nearest whole percentage

6 0

2 years ago

Convert to vertex form:<br><br> y=2x^2-8x+1

Bad White [126]

I’ll try and help u in 6 years

3 0

2 years ago

A store sells 8 colors of balloons with at least 28 of each color. How many different combinations of 28 balloons can be chosen?

Len [333]

Answer:

(a) $Selection = 6724520$

(b) $At\ most\ 12 = 6553976$

(c) $At\ most\ 8 = 6066720$

(d) $At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

Step-by-step explanation:

Given

$Colors = 8$

$Balloons = 28$ --- at least

Solving (a): 28 combinations

From the question, we understand that; a combination of 28 is to be selected. Because the order is not important, we make use of combination.

Also, because repetition is allowed; different balloons of the same kind can be selected over and over again.

So:

$n => 28 + 8-1$ $= 35$

$r = 28$

$Selection = ^{35}^C_{28$

$Selection = \frac{35!}{(35 - 28)!28!}$

$Selection = \frac{35!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29*28!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29}{7!}$

$Selection = \frac{35*34*33*32*31*30*29}{7*6*5*4*3*2*1}$

$Selection = \frac{33891580800}{5040}$

$Selection = 6724520$

Solving (b): At most 12 red balloons

First, we calculate the ways of selecting at least 13 balloons

Out of the 28 balloons, there are 15 balloons remaining (i.e. 28 - 13)

So:

$n => 15 + 8 -1 = 22$

$r = 15$

Selection of at least 13 =

$At\ least\ 13 = ^{22}C_{15}$

$At\ least\ 13 = \frac{22!}{(22-15)!15!}$

$At\ least\ 13 = \frac{22!}{7!15!}$

$At\ least\ 13 = 170544$

Ways of selecting at most 12 =

$At\ most\ 12 = Total - At\ least\ 13$ --- Complement rule

$At\ most\ 12 = 6724520- 170544$

$At\ most\ 12 = 6553976$

Solving (c): At most 8 blue balloons

First, we calculate the ways of selecting at least 9 balloons

Out of the 28 balloons, there are 19 balloons remaining (i.e. 28 - 9)

So:

$n => 19+ 8 -1 = 26$

$r = 19$

Selection of at least 9 =

$At\ least\ 9 = ^{26}C_{19}$

$At\ least\ 9 = \frac{26!}{(26-19)!19!}$

$At\ least\ 9 = \frac{26!}{7!19!}$

$At\ least\ 9 = 657800$

Ways of selecting at most 8 =

$At\ most\ 8 = Total - At\ least\ 9$ --- Complement rule

$At\ most\ 8 = 6724520- 657800$

$At\ most\ 8 = 6066720$

Solving (d): 12 red and 8 blue balloons

First, we calculate the ways for selecting 13 red balloons and 9 blue balloons

Out of the 28 balloons, there are 6 balloons remaining (i.e. 28 - 13 - 9)

So:

$n =6+6-1 = 11$

$r = 6$

Selection =

$^{11}C_6 = \frac{11!}{(11-6)!6!}$

$^{11}C_6 = \frac{11!}{5!6!}$

$^{11}C_6 = 462$

Using inclusion/exclusion rule of two sets:

$Selection = At\ most\ 12 + At\ most\ 8 - (12\ red\ and\ 8\ blue)$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 170544+ 657800- 462$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = Total - Only\ 12\ red\ and\ only\ 8\ blue$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 6724520 - 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

3 0

2 years ago