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lawyer [7]
2 years ago
6

A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes.

Each small box can hold 30 books and each large box can hold 55 books. There were 2 more large boxes sent than small boxes, which altogether can hold 280 books. Determine the number of small boxes sent and the number of large boxes sent.
Mathematics
2 answers:
____ [38]2 years ago
7 0

Answer:

2 small boxes sent and 4 large boxes sent.

Step-by-step explanation:

Let the number of small boxes be S and the number of large boxes by L

Given that there were 2 more large boxes sent than small boxes, then

L = S + 2

Also given that each small box can hold 30 books and each large box can hold 55 books and altogether can hold 280 books.

30S + 55L = 280

Solve both equations simultaneously

30S + 55(S + 2) = 280

85S + 110 = 280

85S = 280 - 110

85S = 170

S = 170/85

S = 2

Since L = S + 2

L = 2 + 2 = 4

The number of small boxes sent and the number of large boxes sent are 2 and 4 respectively.

PSYCHO15rus [73]2 years ago
6 0

Answer:

4 large boxes and 2 small boxes

Step-by-step explanation:

4 X 55 =220 books

2 X 30 =  60 books

Total =   280 books

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Answer:

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One solution

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Step-by-step explanation:

* Lets explain how to solve the problem

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* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

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∵ y = 2x + 2 ⇒ (2)

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