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1 year ago

I have a limited time please help ;-;

Mathematics

2 answers:

RoseWind [281]1 year ago

7 0

Answer:$4

hope this helps

diamong [38]1 year ago

6 0

Jessica saves $4 more a week than Raphael. I took this quiz and it was correct.

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Which is the best approximation for the solution of the system of equations? y = A system of equations. y equals negative StartF

Alla [95]

Answer:

(0.88, 0.65)

Step-by-step explanation:

Given that the two equations of the line are:

y =( -2/5)x + 1 and y = 3x – 2. To find the solution, we have to solve the equations simultaneously.

y =( -2/5)x + 1 . . . 1)

y = 3x – 2 . . . 2)

Subtracting equation 1 from equation 2:

3.4x -3 = 0

3.4x = 3

Dividing through by 3.4

3.4x/3.4 = 3/3.4

x = 0.88

To find y, substitute x = 0.88 in equation 2:

y = 3(0.88) - 2

y = 2.65 - 2

y = 0.65

This means that the solution to the system of equations is the point of intersection of the two lines which is at (0.88, 0.65)

7 0

2 years ago

Read 2 more answers

Triangle SQT is isosceles. The measure of angle STQ is 48°. Triangle S Q T is cut by perpendicular bisector T R. The lengths of

igomit [66]

Answer:

$m\angle STR=24^o$

Step-by-step explanation:

we know that

$m\angle STQ=m\angle STR+m\angle RTQ$ ---> by addition angle postulate

we have

$m\angle STQ=48^o$ ----> given problem

$m\angle STR=m\angle RTQ$ ----> given problem

substitute in the expression above

$48^o=2m\angle STR$

Divide by 2 both sides

$m\angle STR=24^o$

3 0

2 years ago

Read 2 more answers

a motor boat traveled 18 miles down a river in 2 hours but took 4.5 hours to return upstream. Find the rate of the motor boat in

tangare [24]

Answer:

rate of the boat in still water = 6.5 miles / hour

rate of the current = 2.5 miles / hour.

Explanation:

1) Name the two variables:

c: rate of the current

b: rate of the boat in still water:

With that, the net rates of the boat down the river and upstrean are:

down the river: b + c

upstream: b - c

2) Now set the equations for the distance as a function of the times and the rates:

distance = rate × time

downstream: 18 miles = (b + c) × 2 hours

upstream: 18 miles = (b - c) × 4.5 hours

3) Set the system of equations:

18 = 2(b + c) ⇒ 9 = b + c . . . Equation (1)

18 = 4.5 (b - c) ⇒ 4 = b - c . . . Equation (2)

4) Solve the system by elimination:

Add equations (1) and (2): 9 + 4 = 2b

Divide both sides by 2: 13/2 = b

Simplify: b = 6.5

Replace b with 6.5 in equation (2) and solve:

4 = 6.5 - c ⇒ c = 6.5 - 4 = 2.5

5) Results:

b = rate of the boat in still water = 6.5 miles / hour

c = rate of the current = 2.5 miles / hour.

3 0

2 years ago

Read 2 more answers

A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is

MakcuM [25]

Answer:

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 5 minutes

Sample mean, $\bar{x}$ = 4.61 minutes

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.75 minutes

a) First, we design the null and the alternate hypothesis

$H_{0}: \mu = 5\text{ minutes}\\H_A: \mu \neq 5\text{ minutes}$

We use two-tailed t test to perform this hypothesis.

b) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.61 - 5}{\frac{0.75}{\sqrt{15}} } = -2.0139$

c) Now, we calculate the p-value using the standard table.

P-value = 0.0638

d) Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Option a) Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05.

4 0

1 year ago

What is 1/999 as a decimal

juin [17]

Answer:0.001001001001001

Step-by-step explanation: I have no idea. just put it in a calculator

5 0

1 year ago

Read 2 more answers