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2 years ago

10

Judy spent 1 hour and 15 minutes less than Sandy exercising last week Sandy Sprint 50 minutes less than Mary who's been 3 hours

at the gym how long did Judy spend exercising

1 answer:

rjkz [21]2 years ago

6 0

Answer:

Judy spent 55 min at the gym.

Step-by-step explanation:

From the three people that are listed in the problem Mary is the only one we know the actual time she was at the gym which is 3 h. Sandy on the other hand spent 50 minutes less sprinting than Mary, so we have:

Sandy = Mary - 50 minutes

Sandy = 3h - 50 minutes

Sandy = 3*60 - 50

Sandy = 180 - 50 = 130 minutes

Judy spent 1h and 15 min less than Sandy exercising so we have:

Judy = Sandy - 1h 15min

Judy = 130 min - (60 min + 15 min)

Judy = 130 min - 75 min = 55 min

Judy spent 55 min at the gym.

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So you distrubute and get

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Andre45 [30]

Answer:

$\huge\boxed{\sf 2(13+4)}$

Step-by-step explanation:

<u>Given expression is:</u>

26 + 8

The Greatest Common Factor is 2. So, we'll take 2 as common:

=> $\sf 2(13+4)$

After simplifying , we get the same expression:

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<h2>~AnonymousHelper1807</h2>

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2 years ago

In the figure, the ratio of the perimeter of rectangle ABDE to the perimeter of triangle BCD is . The area of polygon ABCDE is s

Gekata [30.6K]

Step 1

Find the perimeter of rectangle ABDE

we know that

the perimeter of rectangle is equal to

$P=2b+2h$

In this problem

$b=ED=2\ units$

$h=AE=6\ units$

substitute

$P=2*2+2*6=16\ units$

Step 2

Find the perimeter of triangle BCD

we know that

the perimeter of triangle is equal to

$P=BD+DC+BC$

In this problem we have

$BD=AE=6\ units$

$DC=BC$

Applying the Pythagoras theorem

$DC^{2}=4^{2}+3^{2}$

$DC^{2}=25$

$DC=5\ units$

substitute

$P=6+5+5=16\ units$

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we have

the perimeter of rectangle is equal to

$P=16\ units$

the perimeter of the triangle is

$P=16\ units$

so

the ratio is equal to

$\frac{16}{16} =1$

therefore

<u>the answer Part 1) is the option B</u>

$1$

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Find the area of polygon ABCDE

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The area of polygon is equal to the sum of the area of rectangle plus the area of triangle

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$A=AE*BD=6*2=12\ units^{2}$

Area of the triangle is equal to

$A=\frac{1}{2}AEh$

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substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

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2 years ago

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denis-greek [22]

Answer:

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2 years ago

Law Incorporation [45]

the correct question Part 1) is
<span>A school photo has dimensions of 2 1/4 inches by 2 3/4 inches. What are the dimensions of the school photo if it is enlarged by a scale factor of 7?

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the answer Part 1) is
</span>the dimensions of the school photo are
15 3/4 in x 19 1/4 in

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if the house in the drawing is 7.5 cm tall
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the answer Part 2) is
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Part 3)</span><span>A photo of a painting has a scale of 3 inches = 2 feet. If the photo is 7.5 inches long, how many feet long is the painting?

we know that
</span>
scale factor=measure in the photo/measure in the painting
measure in the painting=measure in the photo/scale factor
scale factor=3/2---> 1.5 in/ft
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measure in the painting=7.5/1.5----> 5 ft

the answer part 3) is
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2 years ago