Answer:
1/100.
Step-by-step explanation:
So, we can make the following deductions from the information given in the question or problem above.
[1]. "You and your neighbor attempt to use your cordless phones at the same time."
DEDUCTION: Two people are involved, that is you and your neighbor are both involved.
[2]. "Your phones independently select one of ten channels at random to connect to the base unit. "
DEDUCTION: Both cordless phones can choose one channels each which is random. The number of channels available is ten.
Therefore, the probability that both your phone and your neighbor phone pick the same channel can be calculated or determined as follows:
The probability that both your phone and your neighbor phone pick the same channel = probability that both your phone will pick one channel out of the ten channels × the probability that your neighbor phone pick one channel out of the ten channels.
The probability that both your phone and your neighbor phone pick the same channel = 1/10 × 1/10 = 1/100.
Therefore, The probability that both your phone and your neighbor phone pick the same channel = 1/100.
Answer: 17/5
Step-by-step explanation: isolation the variable by dividing each side by factors that don't contain the variable. z=−b5−17
Answer:
See below
Step-by-step explanation:
a) <u>Using the first two lines to get the equation:</u>
Since t = 0 represents a start point, the y-intercept is 163488
<u>Slope is:</u>
- (168392 - 163488)/10 = 490.4
<u>And the equation:</u>
- P(t) = 490.4(t - 1970) + 163488
b) Prediction of the population in 2012 using the function:
- P(2012) = 490.4(2012 - 1970) + 163488 = 184084.8
As we see the number we got is less than the one on the line 3 of the table. So the model underestimated the actual population.
Answer:
you have to put them in order dummy
Step-by-step explanation:
Answer:
The answer is the option A
Step-by-step explanation:
we know that
The lateral area of a right rectangular prism is equal to
where
P is the perimeter of the base
h is the height of the prism
Find the perimeter
substitute in the formula
