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RUDIKE [14]
2 years ago
5

The population of bears in a national forest is changing according to the function N(t)=850(1.04)t , where t is the time in year

s, and N(t) is the number of bears. Which statement explains how the bear population is changing?
Mathematics
1 answer:
larisa86 [58]2 years ago
7 0

Answer:

The statement is that the population increases at a rate of 4% per year

Step-by-step explanation:

The function is given as;

N(t) = 850(1.04)^t

The general equation form for a representation as this is;

P = I(1 + r)^t

Where I is the initial value and P is the present value

r is the rate of increase

t is the time

Thus, we have that;

1 + r = 1.04

r = 1.04-1

r = 0.04

0.04 is same as 4/100 which is same as 4%

So the statement about how the population of bear is changing is that the population increases at a rate of 4% each year

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Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Alona [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

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The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

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