Answer:
In order for a product to be even, at least one factor must be even (so that the product is divisible by 2). The minimum number of even integers she could have chosen is 1, so the maximum number of odd integers she could have chosen is 4 :)
The diagonals would be perpendicular (intersect at a 90* angle)
Answer:
To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic
1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation
We simplify and check the number of real roots with the quadratic formula,
for quadratic equations the form 0 = a·x² - b·x + c
Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.
Step-by-step explanation:
Answer:
The answer is 3
Step-by-step explanation:
B/c 8+2=10 just add one more and 2+1=3
Answer:
X=7 ST=11 RT=17
Step-by-step explanation:
RT=RS+ST. RS= 2(7)-8. ST=11
X+10=2x-8+11. =14-8=6. RT= x+10
X+10=2x+3. RS=6. 7+10=17
10=x+3. RT=17
X=7