Given:
A quadratic function has a line of symmetry at x = –3.5 and a zero at –9.
To find:
The other zero.
Solution:
We know that, the line of symmetry divides the graph of quadratic function in two congruent parts. So, both zeroes are equidistant from the line of symmetry.
It means, line of symmetry passes through the mid point of both zeroes.
Let the other zero be x.

Multiply both sides by 2.

Add 9 on both sides.


Therefore, the other zero of the quadratic function is 2.
Answer:
A
Step-by-step explanation:
Let the smaller room have an area of x^2
Let the larger room have an area of (x + 3)^2
(x+3) ^2 + x^2 = 89 Be careful not to make it 89^2.
x^2 + 6x + 9 + x^2 = 89 Expand the binomial squared
2x^2 + 6x + 9 - 89 = 0 Subtract 89 from both sides
2x^2 + 6x + 9 - 89 = 0 Combine
2x^2 + 6x - 90=0 Divide by 2
x^2 + 3x - 45 = 0 This factors.
(x + 9)(x- 5) = 0
X + 9 gives nothing useful
x - 5 = 0
x = 5
x + 3 = 5+3 = 8
So the answer is A
<u>Answer:</u>
If PQ=RS then PQ and RS have the same length. Hence option D is correct
<u>Solution:</u>
Given that, pq = rs
And, we have to find which of the given options are true.
<u><em>a) pq and rs form a straight angle
</em></u>
We can’t decide the angle in between pq and rs just by the statement pq = rs.
So this statement is false.
<u><em>b) pq and rs form a zero angle.
</em></u>
We can’t decide the angle in between pq and rs just by the statement pq = rs.
So this statement is false.
<u><em>c) pq and rs are same segment.
</em></u>
If two things equal then there is no condition that both represents a single item.
So this statement is false.
<u><em>d) pq and rs have the same length
</em></u>
As given that pq = rs, we can say that they will have the same length
Hence, option d is true.
A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
sqrt 841 = c
29 = c <== third straw will be 29 cm
The formula for the light bend would be n1*sin i= n2 * sin r
If you use "sin (90-x)= cos x" principle, you can change the sin in the equation into
n1*sin i= n2 * sin r
n1 * cos a= n2 * cos b
n2/n1= cos a/ cos b
Assuming the n constant is the ratio of the glass compared to water then the answer would be: cos a/ cos b